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3 years ago

Can you use simplest form to compare 8/10 and 3/5 explain

Mathematics

2 answers:

valentina_108 [34]3 years ago

4 0

Yes,because the denomenators can be both 5... So 8/10=4/5..4/5>3/5

jolli1 [7]3 years ago

3 0

Simplify 8/10
(4*2)/(5*2)
2/2=1

Thus,
8/10=4/5

Now, compare 4/5 and 3/5.
Hope this helps!

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“An architect is planning to incorporate several stone spheres of different sizes into the landscaping of a public park, and wor

Artist 52 [7]

Answer:

Part 1) The value that is closest to the cost of finishing a sphere with a 5.50-meter circumference is $900

Part 2) The value that is closest to the cost of finishing a sphere with a 7.85-meter circumference is $1,800

Step-by-step explanation:

Step 1

Find the radius of each sphere

we know that

The circumference of a circle is equal to

$C=2\pi r$

Find the radius of the sphere with a 5.50-meter circumference

For $C=5.50\ m$

assume

$\pi =3.14$

substitute and solve for r

$5.50=2(3.14)r$

$r=5.50/[2(3.14)]=0.88\ m$

Find the radius of the sphere with a 7.85-meter circumference

For $C=7.85\ m$

assume

$\pi =3.14$

substitute and solve for r

$7.85=2(3.14)r$

$r=7.85/[2(3.14)]=1.25\ m$

step 2

Find the surface area of each sphere

The surface area of sphere is equal to

$SA=4\pi r^{2}$

Find the surface area of sphere with a 5.50-meter circumference

For $r=0.88\ m$

assume

$\pi =3.14$

substitute

$SA=4(3.14)(0.88)^{2}$

$SA=9.73\ m^{2}$

Find the surface area of sphere with a 7.85-meter circumference

For $r=1.25\ m$

assume

$\pi =3.14$

substitute

$SA=4(3.14)(1.25)^{2}$

$SA=19.63\ m^{2}$

step 3

Find the cost of finishing each sphere

we know that

To find out the cost , multiply the surface area by $92 per square meter

Find the cost of sphere with a 5.50-meter circumference

$9.73*(92)=\$895.16$

therefore

The value that is closest to the cost of finishing a sphere with a 5.50-meter circumference is $900

Find the cost of sphere with a 7.85-meter circumference

$19.63*(92)=\$1,805.96$

therefore

The value that is closest to the cost of finishing a sphere with a 7.85-meter circumference is $1,800

6 0

3 years ago

(3x- 1) 71 solve for the equation and x please

Ksivusya [100]

Answer:

x=24

Step-by-step explanation:

The opposite angles are equal as per certain theorems.

3x-1=71

3x=72

x=24

4 0

2 years ago

ABDE is a rectangle on coordinate axes, the sides of the rectangle are parallel to the axes,

Hitman42 [59]

The coordinates of B and D are the location of the vertices B and D in the rectangle

The coordinates of B and D are (55, 30) and (55, 14)

<h3>How to determine the coordinates of B and D?</h3>

From the figure of the rectangle, we have:

A = (25,30)

C = (40, 22)

Point B has the same y-coordinate as point A

So, we have:

B = (x, 30)

The x-coordinate is then calculated as:

Bx = 2Cx - Ax

This gives

Bx = 2*40 - 25

Bx = 55

So, the coordinates of B are:

B = (55, 30)

Point D has the same x-coordinate as point B

So, we have:

D = (55, y)

The y-coordinate is then calculated as:

Dy = Cy - (By - Cy)

This gives

Dy = 22 - (30 - 22)

Dy = 14

So, the coordinates of B are:

D = (55, 14)

Hence, the coordinates of B and D are (55, 30) and (55, 14)

Read more about rectangles at:

brainly.com/question/10737082

8 0

2 years ago

MOON The expression gives the weight of an object on the Moon in pounds with a weight of w pounds on Earth. What is the weight o

dybincka [34]

Answer: 29.7 pounds

Step-by-step explanation:

The expression in question is w/6.

If the weight of an object on earth is w, the weight of the object on the moon is w/2.

The weight of the space suit is therefore:

= 178.2/6

= 29.7 pounds

4 0

2 years ago

Two mechanics worked on a car. The first mechanic charged $65 per hour, and the second mechanic charged $90 per hour. The mechan

Katena32 [7]

Answer:

First mechanic worked 20 hours and second mechanic worked 5 hours

Step-by-step explanation:

Let the number of hours the first mechanic worked = $a$

Let the number of hours the second mechanic worked = $b$

Therefore, we can write 2 equations and then solve them simultaneously:

$a+b=25$

$65a+90b=1750$

Rearranging the first equation: $a=25-b$

and substituting into the second equation to find $b$ :

$65(25-b)+90b=1750$

$1625-65b+90b=1750\\
25b=125\\
b=5$

Now sub $b=5$ into the first equation to find $a$

$a+5=25\\
a=20$

Therefore, first mechanic (a) worked 20 hours and second mechanic (b) worked 5 hours

4 0

2 years ago