To solve the problem you must know that to change from Cartesian to polar coordinates you must write:
x = rcos (θ)
Where "r" is the radius
Likewise y = rsin (θ)
Therefore, in the expression r = 3cos (θ) one can write r as:
r = x / cos (θ)
So:
x / cos (θ) = 3cos (θ)
x = 3cos ^ 2 (θ)
The same for y ...
y = rsin (θ)
y = 3cos (θ) sin (θ).
Finally the correct answer is option 2.
x = 3cos ^ 2 (θ) y = 3cos (θ) sin (θ).
Answer:
(0, 33) : Yes
(4.8, 30.5) : Yes
Step-by-step explanation:
height of at least 24 ft : y >= 24
horizontal distance of no more than 10 ft. : 0 <= x <= 10
The vertical height must be at least three times as high as the horizontal distance. No rocket should go higher than 33 ft.:
y >= 3x and y <= 33
So Constraints:
24 <= y <= 33
y >= 3x
0 <= x <= 10
Now check to see if those coordinate points meet all the constraints
(0, 33) : Yes
(4.8, 30.5) : Yes
(9, 26) : No (because 26 is less than (3 * 9) = 27)
(4, 36)
: No (because 36 > 33, must be 24 <= y <= 33)
(2, 22): No (because 22 <24, must be 24 <= y <= 33)
2+x=50
That is what I would do. I hope this helps!
The expression will be x-3.
Answer:
B
Step-by-step explanation:
Points A,B ,C are all to the left of 0 so they are negative
We want a point -3 1/2
The points A and B are to the left of -3 so they are more negative than -3
A is at -5 so it cannot be -3 1/2
