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2 years ago

Find the nth term for the sequence 20,18,16,14..

Mathematics

1 answer:

Anastasy [175]2 years ago

5 0

Answer:

20-2(n-1)

Step-by-step explanation:

The general term (or the nth term) of this sequence is [20-2(n-1)].

Verification:

1st term = 20-2(1-1) = 20-2(0) = 20-0 = 20

2nd term = 20-2(2-1) = 20-2(1) = 20-2 = 18

3rd term = 20-2(3-1) = 20-2(2) = 20-4 = 16

4th term = 20-2(4-1) = 20-2(3) = 20-6 = 14

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2 years ago

(−2k 3 −7k 2 +5k)+(6k 2 +3k)=

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2 years ago

The LCM of two numbers is 60. Their GCf is 6 and their difference is 18. What are the two numbers?

Aliun [14]

$LCM(x,y)=60\\
GCF(x,y)=6\\
x-y=18\\\\
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|x\cdot y|=360\\
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|x\cdot y|=360\\
x=18+y\\\\
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(y+9)^2=441 \vee (y+9)^2=-279\\
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y=21-9 \vee y=-21-9\\
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x-12=18 \vee x-(-30)=18\\
x=30 \vee x=-12\\\\
\boxed{x=30, y=12 \vee x=-12, y=-30}$

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3 years ago

Read 2 more answers

Given sin(−θ)=−1/6 and tanθ=−√35/35 What is the value of cosθ?

murzikaleks [220]

Answer:

$cos(\theta)=-\frac{\sqrt{35} }{6}$

Step-by-step explanation:

Recall the negative angle identity for the sine function:

$sin(- \theta)=-sin(\theta)$

Then, we can find the value of $sin(\theta)$ :

$sin(\theta)=-sin(-\theta)\\sin(\theta) =-(-\frac{1}{6} )\\sin(\theta)= \frac{1}{6}$

Now recall the definition of the tangent function:

$tan(\theta)=\frac{sin(\theta)}{cos(\theta)}$

Therefore, now that we know the value of $sin(\theta)$ , we can solve in this equation for $cos(\theta)$

$tan(\theta)=\frac{sin(\theta)}{cos(\theta)}\\-\frac{\sqrt{35} }{35} =\frac{1/6}{cos(\theta)} \\cos(\theta)=-\frac{\frac{1}{6} }{\frac{\sqrt{35} }{35} } \\cos(\theta)=-\frac{35}{6\,\sqrt{35} } \\cos(\theta)=-\frac{\sqrt{35} }{6}$

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3 years ago

Which type of transformation maps triangle GFH onto triangle G'F'H'?

lions [1.4K]

Answer:

rotation

Step-by-step explanation:

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3 years ago

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