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2 years ago

I genuinely have no clue how to do them15 here and 15 on another post

Mathematics

1 answer:

Dovator [93]2 years ago

6 0

Step-by-step explanation:

6. angle 1 = angle 4 = 60deg (vertically opposite angles)

7. angle 3 = 180 - 40 - 60 = 80deg (angles on a straight line are supplementary)

8. angle 5 = angle 2 = 40deg (vertically opposite angles)

9. angle 6 = angle 3 = 80deg (vertically opposite angles)

10. angle 7 = angle 5 + angle 4 = 40 + 60 = 100deg (alternate angles, //lines)

11. angle 8 = 180 - 100 = 80deg (angles on a str line are supplementary)

12. angle 9 = 180 - 80 - 40 = 60deg (angles in a triangle)

13. angle 10 = 180 - 60 = 120deg (angles on a str line are supplementary)

14. angle 11 = angle 9 = 60deg (vertically opp angles)

15. angle 12 = angle 10 = 120deg (vertically opp angles)

Topic: angles

If you like to venture further, feel free to check out my insta (learntionary). It would be best if you could give it a follow. I'll be constantly posting math tips and notes! Thanks!

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Find a positive number for which the sum of it and its reciprocal is the smallest (least) possible. Let x be the number and let

Allisa [31]

Answer:

$S(x) = x + \frac{1}{x}$ --- Objective function

Interval = $\{x:x=1\}$

Step-by-step explanation:

Given

Represent the number with x

The required sum can be represented as:

$x + \frac{1}{x}$

Hence, the objective function is:

$S(x) = x + \frac{1}{x}$

To get the the interval, we start by differentiating w.r.t x

Using first principle, this gives:

$S'(x) = 1 - \frac{1}{x^2}$

Equate S'(x) to 0 in order to solve for x

$0 = 1 - \frac{1}{x^2}$

Subtract 1 from both sides

$0 -1 = 1 -1 - \frac{1}{x^2}$

$-1 = - \frac{1}{x^2}$

Multiply both sides by -1

$1 = \frac{1}{x^2}$

Cross Multiply

$x^2 * 1 = 1$

$x^2 = 1$

Take positive square root of both sides because x is positive

$\sqrt{x^2} = \sqrt{1$

$x = 1$

Representing x using interval notation, we have

Interval = $\{x:x=1\}$

To get the smallest sum, we substitute 1 for x in $S(x) = x + \frac{1}{x}$

$S(1) = 1 + \frac{1}{1}$

$S(1) = 1 + 1$

$S(1) = 2$

Hence, the smallest sum is 2

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3 years ago

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3 years ago

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andrew-mc [135]

Answer:

option A

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Step-by-step explanation:

make y subject of formula

x+2y=-8

2y=-8-x

y=(-8-x)/2

y=-4-x/2

when x=-2

y=-4-(-2)/2

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Leno4ka [110]

Answer:

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Step-by-step explanation:

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2 years ago

I genuinely have no clue how to do them15 here and 15 on another post​

I genuinely have no clue how to do them15 here and 15 on another post