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3 years ago

2/3(9 + x)= -5( 4 - x)

Mathematics

1 answer:

MrRa [10]3 years ago

5 0

Answer is 6!
Explanation ; Step by step

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An automated egg carton loader has a 1% probability of cracking an egg, and a customer will complain if more than one egg per do

vaieri [72.5K]

Answer:

a) Binomial distribution B(n=12,p=0.01)

b) P=0.007

c) P=0.999924

d) P=0.366

Step-by-step explanation:

a) The distribution of cracked eggs per dozen should be a binomial distribution B(12,0.01), as it can model 12 independent events.

b) To calculate the probability of having a carton of dozen eggs with more than one cracked egg, we will first calculate the probabilities of having zero or one cracked egg.

$P(k=0)=\binom{12}{0}p^0(1-p)^{12}=1*1*0.99^{12}=1*0.886=0.886\\\\P(k=1)=\binom{12}{1}p^1(1-p)^{11}=12*0.01*0.99^{11}=12*0.01*0.895=0.107$

Then,

$P(k>1)=1-(P(k=0)+P(k=1))=1-(0.886+0.107)=1-0.993=0.007$

c) In this case, the distribution is B(1200,0.01)

$P(k=0)=\binom{1200}{0}p^0(1-p)^{12}=1*1*0.99^{1200}=1* 0.000006 = 0.000006 \\\\ P(k=1)=\binom{1200}{1}p^1(1-p)^{1199}=1200*0.01*0.99^{1199}=1200*0.01* 0.000006 \\\\P(k=1)= 0.00007\\\\\\P(k\leq1)=0.000006+0.000070=0.000076\\\\\\P(k>1)=1-P(k\leq 1)=1-0.000076=0.999924$

d) In this case, the distribution is B(100,0.01)

We can calculate this probability as the probability of having 0 cracked eggs in a batch of 100 eggs.

$P(k=0)=\binom{100}{0}p^0(1-p)^{100}=0.99^{100}=0.366$

5 0

3 years ago

What is the length of the missing side if<br>Side A: 8in <br>Side B: ?<br>Side C: 14 in

Illusion [34]

Answer:

side b= 11.489

Step-by-step explanation:

well I'm doing the exact same lesson currently and I just did the test on this exact question soo yeahh

6 0

3 years ago

Pls help me

Kruka [31]

Answer:

A = pi x r²

A = pi x 8²

A = 64pi

Step-by-step explanation:

I hope this helps :D

5 0

3 years ago

Read 2 more answers

a 24 foot tall streetlight casts a shadow that is 18 feet long. how long of a shadow is cast by a nearby parking meter post that

Elanso [62]

9514 1404 393

Answer:

3 ft

Step-by-step explanation:

The post is 4/24 = 1/6 as tall as the streetlight, so we expect its shadow to be 1/6 as long as that of the streetlight:

(1/6)(18 ft) = 3 ft

The parking meter post shadow is 3 feet long.

3 0

3 years ago

Find value of x<br> (pics below)

salantis [7]

I may be wrong but I believe that the answer is 8.

4 0

3 years ago