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3 years ago

20 POINTS FOR AN ANSWER PLEASE!!!

Mathematics

1 answer:

Anna007 [38]3 years ago

7 0

Answer:12 feet

Step-by-steps:

1cm:4ft

4x3=12

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Question 11

dem82 [27]

Answer:

There were 49 questions on this Geometry test.

Step-by-step explanation:

You can start by setting up a proportion:

x = total number of questions on Geometry test

$\frac{37}{x}$ = $\frac{75.51}{100}$

Now, to solve for x, cross multiply:

75.51x = 3700

Finally, isolate x and solve:

x = 49.0001324328

This is very close to 49.

3 0

3 years ago

Question in picture A) 16/63 B)-16/63 C) 63/16 D) -63/16

Orlov [11]

ANSWER
$\tan(x + y) = - \frac{63}{16}$

EXPLANATION

We were given that,

$\csc(x) = \frac{5}{3}$

This implies that,

$\sin(x) = \frac{3}{5}$

We use the Pythagorean identity

$\sin^{2} (x) + \cos^{2} (x)= 1$
to get,

$\cos(x) = \sqrt{1 - ( { \frac{3}{5} })^{2}} = \frac{4}{5}$

We were also given that,

$\cos(y) = \frac{5}{13}$

This means that,

$\sin(y) = \sqrt{1 - {( \frac{5}{13}) }^{2} } = \frac{12}{13}$

This is because,

$0 < \: x \: < \frac{\pi}{2}$

$0 < \: y \: < \frac{\pi}{2}$

This angles are in the first quadrant so we pick the positive values.

$\tan(x + y) = \frac{ \sin(x + y) }{ \cos(x + y) }$

$\tan(x + y) = \frac{ \sin(x ) \cos(y) + \sin(y) \cos(x) }{ \cos(x) \cos(y) - \sin(x) \sin(y) }$

$\tan(x + y) = \frac{ \frac{3}{5} \times \frac{5}{13} + \frac{12}{13} \times \frac{4}{5} }{ \frac{4}{5} \times \frac{5}{13} - \frac{3}{5} \times \frac{12}{13} }$

$\tan(x + y) = - \frac{63}{16}$

The correct answer is D

4 0

3 years ago

Simon put $15000 in an account with a simple interest rate of 4.5%. How much interest will be earned after 8 years?

Leto [7]

$~~~~~~ \textit{Simple Interest Earned} \\\\ I = Prt\qquad \begin{cases} I=\textit{interest earned}\\ P=\textit{original amount deposited}\dotfill & \$15000\\ r=rate\to 4.5\%\to \frac{4.5}{100}\dotfill &0.045\\ t=years\dotfill &8 \end{cases} \\\\\\ I = (15000)(0.045)(8)\implies I=5400$

4 0

2 years ago

Find the area of a circle with a radius of 3

Mice21 [21]

The answer is 28.27

8 0

3 years ago

Kane is trading for a marathon he starts running 3 miles during every training season each week plans to increase the distance o

Contact [7]

Answer:

(11+w)/4

Step-by-step explanation:

Let the first term be 3 miles

If he plans to increase the distance of his run by 1/4 mile, then

common difference = 1/4

To get the distance Kane runs in a training session after w weeks , we will use the nth term of an AP

Tw = a+(w-1)d

Tw = 3 + (w-1)(1/4)

Tw = 3 + 1/4 w - 1/4

Tw = 11/4 + 1/4 w

Tw = (11+w)/4

Hence the distance Kane runs in a training session after w weeks is (11+w)/4 weeks

4 0

3 years ago