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Alja [10]
2 years ago
10

A circle has a mass of 3 grams and a triangle has a mass of 5 grams write an equation for the hanger

Mathematics
1 answer:
Neko [114]2 years ago
8 0

Answer:

The fraction can not be reduced, but it can be converted to decimal form.

Exact Form:

3/5

Decimal Form: 0.6

Step-by-step explanation:

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Sum is 30

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Find, correct to four decimal places, the length of the curve of intersection of the cylinder 4x2 1 y2 − 4 and the plane x 1 y 1
charle [14.2K]

<u>Answer-</u> Length of the curve of intersection is 13.5191 sq.units

<u>Solution-</u>

As the equation of the cylinder is in rectangular for, so we have to convert it into parametric form with

x = cos t, y = 2 sin t   (∵ 4x² + y² = 4 ⇒ 4cos²t + 4sin²t = 4, then it will satisfy the equation)

Then, substituting these values in the plane equation to get the z parameter,

cos t + 2sin t + z = 2

⇒ z = 2 - cos t - 2sin t

∴ \frac{dx}{dt} = -\sin t

  \frac{dy}{dt} = 2 \cos t

  \frac{dz}{dt} = \sin t-2cos t

As it is a full revolution around the original cylinder is from 0 to 2π, so we have to integrate from 0 to 2π

∴ Arc length

= \int_{0}^{2\pi}\sqrt{(\frac{dx}{dt})^{2}+(\frac{dy}{dt})^{2}+(\frac{dz}{dt})^{2}

=\int_{0}^{2\pi}\sqrt{(-\sin t)^{2}+(2\cos t)^{2}+(\sin t-2\cos t)^{2}

=\int_{0}^{2\pi}\sqrt{(2\sin t)^{2}+(8\cos t)^{2}-(4\sin t\cos t)

Now evaluating the integral using calculator,

=\int_{0}^{2\pi}\sqrt{(2\sin t)^{2}+(8\cos t)^{2}-(4\sin t\cos t) = 13.5191




8 0
3 years ago
2x - y = 6<br>4<br>x-y<br>13<br>anch​
yanalaym [24]

Answer:

x=-7, y= -20

Step-by-step explanation:

2x - y =6

x - y = 13

when I subract (x-y =13 ) from (2x-y =6)

2x -y =6

-x +y=-13

______________

x = -7

substitute x=-7 in the second equation

-7 - y =13

-y = 13 +7

-Y = 20

Y=-20

x=-7, y= -20

8 0
3 years ago
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