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Viefleur [7K]
3 years ago
7

The sum of two numbers is 100,the first number is 12 less than the second number? What equation would represent this equation

Mathematics
1 answer:
kherson [118]3 years ago
5 0

Step-by-step explanation:

Let the first number be x and the second y

x+y=100

(x-12)+y

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The boy the apartment building is filling a pool 30 ft long 20 feet wide and 5 feet deep it has been filled 4 ft deep how many m
inn [45]
Capacity of the pool = 30 x 20 x  5 = 3000 ft³

Amount of water already filled = 30 x 20 x 4 = 2400 ft²

Amount of water needed to full the pool = 3000 - 2400 = 600 ft²


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Answer: 600 ft² of water is needed to fill up the pool.
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4 0
4 years ago
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Write an expression for the perimeter of the triangle shown in the picture
umka2103 [35]

Answer: x-5+5+5

Step-by-step explanation:

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3 years ago
Find a ⋅ b. a = <5, 2>, b = <4, 5>
cestrela7 [59]

Answer:

  30

Step-by-step explanation:

For a = <xa, ya> and b = <xb, yb>, the dot product is the sum of products ...

  a·b = (xa)(xb) + (ya)(yb)

Substituting the given information, you have ...

  a·b = 5·4 + 2·5 = 20 + 10

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Some graphing calculators can do such math. There are also dot product calculators available on the Internet. If you have quite a few of these to calculate, you can put the appropriate formula into a spreadsheet.

6 0
3 years ago
A triangle ABC has its vertices at A(-2, -3), B(2, 1), and C(5,-1).
maksim [4K]

~\hfill \stackrel{\textit{\large distance between 2 points}}{d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}}~\hfill ~ \\\\[-0.35em] ~\dotfill\\\\ A(\stackrel{x_1}{-2}~,~\stackrel{y_1}{-3})\qquad B(\stackrel{x_2}{2}~,~\stackrel{y_2}{1}) ~\hfill AB=\sqrt{( 2- (-2))^2 + ( 1- (-3))^2} \\\\\\ AB=\sqrt{(2+2)^2+(1+3)^2}\implies AB=\sqrt{32}\implies \boxed{AB=4\sqrt{2}} \\\\[-0.35em] ~\dotfill

B(\stackrel{x_1}{2}~,~\stackrel{y_1}{1})\qquad C(\stackrel{x_2}{5}~,~\stackrel{y_2}{-1}) ~\hfill BC=\sqrt{( 5- 2)^2 + ( -1- 1)^2} \\\\\\ BC=\sqrt{3^2+(-2)^2}\implies BC=\sqrt{9+4}\implies \boxed{BC=\sqrt{13}} \\\\[-0.35em] ~\dotfill\\\\ C(\stackrel{x_1}{5}~,~\stackrel{y_1}{-1})\qquad A(\stackrel{x_2}{-2}~,~\stackrel{y_2}{-3}) ~\hfill CA=\sqrt{( -2- 5)^2 + ( -3- (-1))^2} \\\\\\ CA=\sqrt{(-7)^2+(-3+1)^2}\implies CA=\sqrt{49+(-2)^2}\implies \boxed{CA=\sqrt{53}}

\stackrel{\textit{\large perimeter of ABC}}{4\sqrt{2}+\sqrt{13}+\sqrt{53}~~\approx~~ 16.54}

3 0
2 years ago
What is the range of y= x + 2?
Lelu [443]

Answer:

A) all real numbers greater than or equal to 2

Domain: x\geq 0

Step-by-step explanation:

The variable in the radical <em>x </em>cannot be less than 0 as that wouldn’t be defined. So, the maximum that <em>x </em>can be is 0, and y=x+2. So, 0+2=2, and <em>y </em>is greater than or equal to 2.

Domain is x is greater than or equal to 0 because you cannot square a negative. So, it must not be less than 0. It could be 0 because square root of 0 is just 0.

7 0
3 years ago
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