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3 years ago

8

35 is less than the difference of 21 and a number

1 answer:

My name is Ann [436]3 years ago

3 0

It's 35<21-n because 35 is less that 21 and an unknown number

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Write an equation of the parabola in vertex form.

GenaCL600 [577]

Vertex Form of Quadratic Equation - MathBitsNotebook(A1 - CCSS Math) f (x) = a(x - h)2 + k, where (h, k) is the vertex of the parabola. FYI: Different textbooks have different interpretations of the reference "standard form" of a quadratic function...:)

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3 years ago

Two Step Equation's and Inequalities -8=2-4y

pantera1 [17]

-8=2-4y
-10=-4y
y=5/2 or 2 1/2 or 2.5

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3 years ago

Read 2 more answers

Tommy the Dunker's performance on the basketball court is influenced by his state of mind: If he scores, he is twice as likely t

rjkz [21]

Answer:

Step-by-step explanation:

Probability of of winning next shot if he scores= 0.5

Probability of missing next shot if he misses = 1/6

a) Probability of scoring 2 shots later if he missed = (1-1/6)^2

=(5/6)^2

=25/36

b) % of successful shots= (1/2+5/6×(1/100))%

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2 years ago

In rectangle ABCD, AC = -x + 21, BP = -9x + 19, and DP = -y + 5. Find the value of y.

creativ13 [48]

Answer:

y=-5

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

The diagonals of a rectangle are equal and bisect each other

so

$BP=\frac{1}{2}AC$

$DP=BP$

step 1

Find the value of x

$BP=\frac{1}{2}AC$

substitute the given values

$(-9x+19)=\frac{1}{2} (-x+21)$

solve for x

Multiply by 2 both sides

$-18x+38=-x+21$

$18x-x=38-21\\17x=17\\x=1$

step 2

Find the value of y

$DP=BP$

we have

$BP=-9x+19$

$DP=-y+5$

substitute

$-y+5=-9x+19$

substitute the value of x

$-y+5=-9(1)+19\\-y+5=10\\y=5-10\\y=-5$

5 0

3 years ago

Which choice is equivalent to the quotient shown here when x is greater than or equal to 0?

Dima020 [189]

Answer: OPTION C

Step-by-step explanation:

Remember that:

$\sqrt[n]{a^n}=a$

And the Product of powers property establishes that:

$a^m*a^n=a^{(mn)}$

Rewrite the expression:

$\frac{\sqrt{18x} }{\sqrt{32} }$

Descompose 18 and 32 into their prime factors:

$18=2*3*3=2*3^2\\32=2*2*2*2*2=2^5=2^4*2$

Substitute into the expression, then:

$\frac{\sqrt{(2*3^2)x} }{\sqrt{2^4*2} }$

Finally,simplifying, you get:

$\frac{3\sqrt{(2)x} }{2^2\sqrt{2} }=\frac{3\sqrt{2x}}{4\sqrt{2}}=\frac{(3)(\sqrt{x})(\sqrt{2})}{(4)(\sqrt{2})}= \frac{3\sqrt{x}}{4}$

8 0

3 years ago