What is the equation of a horizontal line that passes through (6,8)

Mathematics

1 answer:

Doss [256]3 years ago

5 0

Answer:

y=8

Step-by-step explanation:

All horizontals lines are going to be equations of y=y

(6,8)

(x,y)

y=8

You might be interested in

Determine whether the relation describe c as a function of w.

Delicious77 [7]

Answer:

Function:

c = f(w) = 0.49, 0 < w ≤ 1

= 0.70, 1 < w ≤ 2

= 0.91, 2 < w ≤ 3

Step-by-step explanation:

Yes, the relation described can be interpreted as a function.

Here, c is the cost of a mail letter. c depends upon w, which is the weights of the mail letter.

As described in the question, the relation can be expressed as a function.

c can be expressed as a function of w in the following manner:

c(cost of mail) = f(w), where w is the independent variable and c is the dependent variable

c = f(w) = 0.49, 0 < w ≤ 1

= 0.70, 1 < w ≤ 2

= 0.91, 2 < w ≤ 3

where, c is in dollars and w is in ounces.

5 0

4 years ago

What is the slope of the line given by the equation below?<br><br>y = 5x - 6

Bogdan [553]

Slope-intercept form is y = mx + b, where m is the slope of the line and b is the y-intercept.
For the equation y = 5x - 6, m = 5, meaning that the slope of the line is 5.

4 0

3 years ago

Read 2 more answers

A sphere has a radius of 16 in. Which statements about the sphere are true? Check all that apply.

Wewaii [24]

Answer:

The sphere has a diameter of 32 in. CORRECT: the diameter of a sphere doubles its radio, so if the radio equals 16,the diameter measures the double, in this case, 32.
The radius' lenght is one half the length of the diameter. CORRECT: , by definition, the diameter is the maximum distance between two opposite points on the surface of the sphere, and its lenght equals twice the radius because the radius is the distance between the center of the sphere and any point of the frontier of the sphere (then, one colud imagine that the distance between two opposite points in a sphere can be united by two radius, or a diameter).
The volume (V) of a sphere can be calculated as $\frac{4\pi r^3}{3}$ , where r is the radio. In this case, the volume of the sphere will be $\frac{4\pi\times16^3}{3}=\frac{4\pi\times4096}{3}$ , which is also equal to $\frac{16384\times\pi}{3}$ .