Answer:
{3¢, 28¢} or {4¢, 19¢} or {7¢, 10¢}
Step-by-step explanation:
54 = 1×54 = 2×27 = 3×18 = 6×9
Possible values of the stamps are 1 more than the values of a pair of factors. Of course, a 2¢ and 55¢ stamp will not permit paying 54¢ in postage, so that combination won't work. However, other pairs that will work are ...
- 3¢ and 28¢
- 4¢ and 19¢
- 7¢ and 10¢
28. Surface Area
This is some sort of house-like model so for every face we see there's a congruent one that's hidden. We'll just double the area we can see.
Area = 2 × ( [14×9 rectangle] + 2[15×9 rectangle]+[triangle base 14, height 6] )
Let's separate the area into the area of the front and the sides; the front will help us for problem 29.
Front = [14×9 rectangle] + [triangle base 14, height 6]
= 14×9 + (1/2)(14)(6) = 14(9 + 3) = 14×12 = 168 sq ft
OneSide = 2[15×9 rectangle] = 30×9 = 270 sq ft
Surface Area = 2(168 + 270) = 876 sq ft
Answer: D) 876 sq ft
29. Volume of an extruded shape is area of the base, here the front, times the height, here 15 feet.
Volume = 168 * 15 = 2520 cubic ft
Answer: D) 2520 cubic ft
Answer: Andrew = 20
Jimmy = 25
Richard = 100
Step-by-step explanation:
Let the number of Andrew's comic books be y.
Jimmy has five more comic books than Andrew. This means Jimmy has: y+5
Richard has four times as many comic book as jimmy. This means Richard has: 4(y+5) = 4y + 20
Since there are 145 comic books together. This can be rewritten as:
y + (y+5) + (4y+20) = 145
6y+25 = 145
6y = 145 - 25
y = 120/6
y = 20
Andrew has 20 comic books
Jimmy has five more comic books than Andrew. Jimmy has: 20+5 = 25
Richard has: 4y + 20 = 4(20) + 20 = 100
Answer:
Step-by-step explanation:
As an improper fraction
