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2 years ago

If f(x)=3x squared -2x + 1 what is f(x-2)

Mathematics

1 answer:

meriva2 years ago

5 0

Answer:

f(x-2) = 3x^2 - 14x + 17

Step-by-step explanation:

All you have to do is put (x-2) for every x:

3(x-2)^2 - 2(x-2) + 1

Make sure you FOIL (x-2)^2 first:

x^2 - 4x + 4

Now distribute the 3:

3x^2 - 12x + 12

Now distribute the 2 in the 2(x-2):

3x^2 - 12x + 12 - 2x + 4 + 1

Combine like terms:

3x^2 - 14x + 17 = f(x-2)

Hope that helps!

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All 5 students in Mrs. Awful's class got a 50 on the test. For the next test, one of the students got 100 but the remaining 4 st

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Data on first test: 50, 50, 50, 50, 50
Mean = 250 / 5 = 50

In the next test, Data is: 50, 50, 50, 50, 100

Mean = sum of data / number of data
Mean = 50 + 50 + 50 + 50 + 100 / 5
M = 300 / 5
M = 60

In short, Your Answer would be 60

If You're looking for combined progress (average of class then, it would be: 50 + 60 /2 = 110/2 = 55

Hope this helps!

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3 years ago

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Container 1 has 8 items, 3 of which are defective. Container 2 has 5 items, 2 of which are defective. If one item is drawn from

e-lub [12.9K]

Answer:

The required probability is $\frac{19}{40}$

Step-by-step explanation:

The probability of obtaining a defective item from container 1 is $P(E_1)=\frac{3}{8}$

The probability of obtaining a good item from container 1 is $P(E_1)=\frac{5}{8}$

The probability of obtaining a defective item from container 2 is $P(E_1)=\frac{2}{5}$

The probability of obtaining a good item from container 2 is $P(E_1)=\frac{3}{5}$

The cases of the event are

1)Defective item is drawn from container 1 and good item is drawn from container 2

2)Defective item is drawn from container 2 and good item is drawn from container 1

Thus the required probability is the sum of above 2 cases

$P(Event)=\frac{3}{8}\times \frac{3}{5}+\frac{5}{8}\times \frac{2}{5}=\frac{19}{40}$

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3 years ago