Answer:
hon you never asked a question or added an image. id be happy to try and help if you do!
Answer:
Step-by-step explanation:
There are two consecutive positive even integers such that the square of the first is 364 more than five times a second. What are the two numbers?
Two consecutive year positive integers are represented by
x and x + 1
First integer = x
Second integer = y
There are two consecutive positive even integers such that the square of the first is 364 more than five times a second.
This is represented mathematically as:
x² = 364 + 5(x + 1)
x² = 364 + 5x + 5
x² -5x -5 - 364
x² - 5x - 369
Answer: the answer is
=3
−19x−14
Step-by-step explanation: (x−7)(3x+2)
=(x+−7)(3x+2)
=(x)(3x)+(x)(2)+(−7)(3x)+(−7)(2)
=3x2+2x−21x−14
=3x2−19x−14
