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aliya0001 [1]
3 years ago
11

Two of the known angles in a trianglemeasure 120 and 22 What is the measure of the third angle?

Mathematics
1 answer:
emmasim [6.3K]3 years ago
8 0

Answer:

120+22+x=180

x=38

120+22+38=180

Step-by-step explanation:

Hope it helps

Mark me as brainiest

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The school cafeteria sells two types of wraps vegetarian and chicken the vegetarian wrap costs $1.00 and the chicken wrap costs
IRINA_888 [86]

Answer:

35

Step-by-step explanation:

Let's make a system of equations for the vegetarian and chicken wraps; one for the total cost of them and one for the total amount sold.

Vegetarian wraps will be represented by variable v and chicken wraps will be represented by the variable c.

  • v + 3.40c = 266.20
  • v + c = 103

Subtract these equations.

  • 2.40c = 163.20

Divide both sides by 2.40.

  • c = 68

Substitute this value for c into the second equation.

  • v + (68) = 103

Subtract 68 from both sides.

  • v = 35  

The number of vegetarian wraps sold amounted to 35 in total.

3 0
3 years ago
Read 2 more answers
Find the measure of angle A
kow [346]

Answer:

A=45

Step-by-step explanation:

If you take a pencil and put it in the middle of the line it looks like it could be half of the other side

180-45=135

8 0
3 years ago
Solve.
Nikitich [7]
The answer to this is B
4 0
3 years ago
Read 2 more answers
4. Find the standard from of the equation of a hyperbola whose foci are (-1,2), (5,2) and its vertices are end points of the dia
Ad libitum [116K]

The <em>standard</em> form of the equation of the hyperbola that satisfies all conditions is (x - 2)²/4 - (y - 2)²/5 = 1 .

<h3>How to find the standard equation of a hyperbola</h3>

In this problem we must determine the equation of the hyperbola in its <em>standard</em> form from the coordinates of the foci and a <em>general</em> equation of a circle. Based on the location of the foci, we see that the axis of symmetry of the hyperbola is parallel to the x-axis. Besides, the center of the hyperbola is the midpoint of the line segment with the foci as endpoints:

(h, k) = 0.5 · (- 1, 2) + 0.5 · (5, 2)

(h, k) = (2, 2)

To determine whether it is possible that the vertices are endpoints of the diameter of the circle, we proceed to modify the <em>general</em> equation of the circle into its <em>standard</em> form.

If the vertices of the hyperbola are endpoints of the diameter of the circle, then the center of the circle must be the midpoint of the line segment. By algebra we find that:

x² + y² - 4 · x - 4 · y + 4= 0​

(x² - 4 · x + 4) + (y² - 4 · y + 4) = 4

(x - 2)² + (y - 2)² = 2²

The center of the circle is the midpoint of the line segment. Now we proceed to determine the vertices of the hyperbola:

V₁(x, y) = (0, 2), V₂(x, y) = (4, 2)

And the distance from the center to any of the vertices is 2 (<em>semi-major</em> distance, a) and the semi-minor distance is:

b = √(c² - a²)

b = √(3² - 2²)

b = √5

Therefore, the <em>standard</em> form of the equation of the hyperbola that satisfies all conditions is (x - 2)²/4 - (y - 2)²/5 = 1 .

To learn more on hyperbolae: brainly.com/question/27799190

#SPJ1

5 0
2 years ago
A function is graphed on a coordinate grid. As the domain values approach infinity, the range values approach infinity. As the d
noname [10]
Answer: cube root.

Cube root is the only one from the four functions given that has range from negative infinity to infinity.
6 0
3 years ago
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