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damaskus [11]
2 years ago
14

given the following exponential function identify whether the change represents growth or decay y= 56(0.91)^x

Mathematics
1 answer:
OleMash [197]2 years ago
3 0

Answer:

Decay

Step-by-step explanation:

Any "r" value between 0 and 1 indicates an exponential function in decay. The "r" value is the one in the parentheses and raised to the exponent. In this case, the value is 0.91. This number falls within the "r" value boundaries of a decaying exponential function.

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A sphere and a cylinder have the same radius and height. The volume of the cylinder is 27 pi feet cubed.
LenaWriter [7]

Answer:

C. V = two-thirds (27)

Step-by-step explanation:

Given

Solid Shapes: Cylinder and Sphere

Volume of Cylinder = 27π ft³

Required

Volume of the sphere.

From the question,

<u>We have that</u>

1.  The volume of the sphere is the same as the volume of the cylinder

2. The height of the sphere is the same as the height of the cylinder.

From (2) above;

This means that the height of the cylinder equals the diameter of the sphere.

Let h represent the height of the sphere and d represent the diameter of sphere.

Mathematical, d = h

Recall that radius, r = r = \frac{d}{2}

Substitute h for d in the above expression

r = \frac{h}{2}. ----- (take note of this)

Calculating the volume of a cylinder.

V = πr²h

Recall that  V = 27; This gives us

27 = πr²h

Divide both sides by h

\pi r^2 = \frac{27}{h}

-------------------

Calculating the volume of a sphere

V = \frac{4}{3}\pi r^3

Expand the above expression

V = \frac{4}{3}\pi r^2 * r

Substitute \pi r^2 = \frac{27}{h}

V = \frac{4}{3} * \frac{27}{h} * r

Recall that r = \frac{h}{2}

So,

V = \frac{4}{3} * \frac{27}{h} * \frac{h}{2}

V = \frac{4}{3} * \frac{27}{2}

V = \frac{2}{3} * 27

V = \frac{2}{3} (27)

V = two-third (27)

4 0
3 years ago
I need to know what y is equal to. <br> 3/4 = 5/6 + y
irina1246 [14]
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.75 = .84 + Y

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7 0
3 years ago
Read 2 more answers
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Lubov Fominskaja [6]

Answer:

There is no exponential function passing through (1,1) and (5,5).

Step-by-step explanation:

We have the following exponential function

y = Ce^{kt}

The function passes through these two points:

(1,1): This means that when t = 1, y = 1

(5,5): This means that when t = 5, y = 5.

So

(1,1)

y = Ce^{kt}

Ce^{k} = 1

e^{k} = \frac{1}{C}

(5,5)

y = Ce^{kt}

5Ce^{k} = 1

Ce^{k} = \frac{1}{5}

From above, we have that:

e^{k} = \frac{1}{C}

C\frac{1}{C} = \frac{1}{5}

1 = \frac{1}{5}

1 cannot be equal to 1/5, so this is wrong.

This means that there is no exponential function passing through (1,1) and (5,5).

5 0
3 years ago
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jeka57 [31]

Answer:

where is the question

Step-by-step explanation:

I don't see it.

3 0
2 years ago
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densk [106]
I dont quite undeerstand but the gcf for both are..., if that helps is 4 because
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4 0
3 years ago
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