Solve the linear system of equations using the linear combination method.

After a snowstorm in the town of Golden Glen, the morning temperature was – 10°F. But by the afternoon, the temperature had rise

spayn [35]

Answer:

7°F

Step-by-step explanation:

We have the following information from the question;

Morning temperature = -10°F

Increase in temperate = 17°F

Afternoon temperature = the unknown

Since;

Increase in temperature = Afternoon temperature - morning temperature

Then;

Afternoon temperature = increase in temperature + morning temperature

Afternoon temperature = 17°F + (-10°F)

Afternoon temperature= 7°F

5 0

3 years ago

ANSWER THIS ASAP DONT SEND A FILE AT ALL !! I NEED THE ANSWER TO QUESTION 1!!

dimulka [17.4K]

The fourth one, (3,-6), (3,-4), (6,-4), (6,-6)

8 0

3 years ago

In ΔTUV, t = 410 cm, ∠U=27° and ∠V=78°. Find the length of v, to the nearest 10th of a centimeter.

telo118 [61]

Answer:

$v \approx 415.2\,cm$

Step-by-step explanation:

The angle T is:

$\angle T = 180^{\circ} - 27^{\circ} - 78^{\circ}$

$\angle T = 75^{\circ}$

Now, the length of v is determine by the Law of Sines:

$\frac{410\,cm}{\sin 75^{\circ}} = \frac{v}{\sin 78^{\circ}}$

$v = (410\,cm)\cdot \left(\frac{\sin 78^{\circ}}{\sin 75^{\circ}} \right)$

$v \approx 415.2\,cm$

6 0

3 years ago

According to the University of Nevada Center for Logistics Management, 6% of all merchandise sold in the United States gets retu

jeka57 [31]

Answer:

$p_v =P(z>3.390)=0.000349$

If we compare the p value and the significance level given $\alpha=0.1$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 10% of significance the proportion of returns at the Houston store is significantly higher than 0.06 or 6%.

Step-by-step explanation:

1) Data given and notation n

n=80 represent the random sample taken

X=12 represent number of items returned

$\hat p=\frac{12}{80}=0.15$ estimated proportion of items returned

$p_o=0.06$ is the value that we want to test

$\alpha=0.1$ represent the significance level

Confidence=90% or 0.90

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

2) Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that proportion of returns at the Houston store was more than the national expectation (0.06):

Null hypothesis: $p\leq 0.06$

Alternative hypothesis: $p >0.06$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

3) Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.15 -0.06}{\sqrt{\frac{0.06(1-0.06)}{80}}}=3.390$

4) Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.1$ . The next step would be calculate the p value for this test.

Since is a right tailed test the p value would be:

$p_v =P(z>3.390)=0.000349$

If we compare the p value and the significance level given $\alpha=0.1$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 10% of significance the proportion of returns at the Houston store is significantly higher than 0.06 or 6%.

4 0

3 years ago

What is the area of this face? <br> Pleaseeee help asap

Maksim231197 [3]

The answer is 28 because 10x2 is 20 and there are 2 2x2 which is 8 so 28.

6 0

3 years ago

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