Answer: The answer is (b) (2, ∞)
Step-by-step explanation: We are given a function f(x) in the figure and we are to select out of the given options that accurately shows the range of the function defined.
Therefore, the range of the function f(x) will be greater then or equal to 2. So, the range will be [2, ∞).
Thus, the correct option is (b) (2, ∞).
Answer:
a^2*c^2
Step-by-step explanation: im pretty sure this is it
Answer:
3- (-5) + -2.
Step-by-step explanation:
Anything plus a negative number will either make that negative number go closer to zero, or turn into a positive number.
The possible solution to the equation given is 3 and -1/3
<h3>Laws of logarithm</h3>
Given the logarithmic expression given as:
log,(8x) – log,(x^2 - 1) = log, 3
Applying the product and quotient rule will give:
log(8x/x^2-1) = log3
8x/x^2-1 = 3
Cross multiply
8x = 3x^2 - 3
3x^2 - 8x - 3 = 0
3x^2 -9x + x - 3 = 0
3x(x-3)+1(x-3)
x - 3 = 0 and 3x = -1
x = 3 and -1/3
Hence the possible solution to the equation given is 3 and -1/3
Learn more on logarithm here: brainly.com/question/25710806
F(x) = 1/x is a special function. is called the multiplicative inverse or the reciprocal function. the specific shape of the graph is called a rectangular hyperbola.
negative values of x with produce negative values of f(x) and positive values will produce positive function values. so this hyperbola is symmetric with respect to the origin and all negative values are in Q3 and all positive values are in Q1.
as x gets farther and farther from 0 in either direction, you can see that 1/x will be an ever-increasingly smaller distance from the x-axis. indeed, the limit of this function is zero as x approaches either positive or negative infinity.
if x is between -1 and 1, then the value of f(x) increases until x = 0, the limit of the function as x approaches 0 being positive and negative infinity depending on which direction you are coming from.
the domain is all real numbers with the exception of 0
the range also happens to be all real numbers with the exception of zero. all that really means is that zero has no multiplicative inverse.
strictly speaking, this is an exponential function, as the function is f(x) = x^(-1).
