Maximum height is at dH/dt=0
H= -16T^2+80T+5
dH/dt=-32T+80
-32T+80=0
32T=80
T=2.5s when height is max
Hmax=-16(2.5)^2+80*2.5)+5
=105ft
catching the ball at 5' means solve for T at H=5
H= -16T^2+80T+5=5
-16T^2+80T=0
-16T(T-5)=0
so T=0 cannot be the ans or T=5s
Twelve times 3 added to three is equal to?
Answer:
48
Step-by-step explanation:
Answer:
5/6
Step-by-step explanation:
0.41/1.33=0.3125=5/6
