A piece-wise function combines more than one functions of different input values.
<em>The value of f(-1) is -3</em>
From the graph, we have the following observations
- <em>When x = -1, y = -3</em>
- <em>When x = -1, y = -4</em>
Notice that there is a closed circle at the point where x = -1 and y = -3.
This means that y = -3 is inclusive of the values of y on that particular function
However, there is an open circle at the point where x = -1 and y = -3.
This means that y = -4 is exclusive of the values of y on that particular function
The correct corresponding value of y is when y is inclusive.
Hence, the value of f(-1) is -3
See attachment for the graph of the piece-wise functions
Read more about piece-wise functions at:
brainly.com/question/11547854
Answer:
SAS
Step-by-step explanation:
Given: Two triangles ΔABD and ΔDCA,
We have, AD=AD (common)
∠A=∠A (Given)
BA=CD (Sides opposite to equal angles are always equal)
With the SAS rule of congruency,
ΔABD≅ΔDCA
The probability = outcome/total outcomes
The total of the outcomes is the total number of the letters of the given word, then
The total outcomes = 11
The outcome is the number of letter "s" in the word
The outcome = 4, then
The probability of "s" is
To change it to percent multiply it by 100% and round it to the nearest 1 decimal place
The answer is 36.4%
Answer C
Answer: Let "T" denote households with television
"I" denote households with internet
and "N" denote households with neither of these.
Since P(N) = 0.05 then it means P(TuI) = 0.95. We know from set theory that P(TuI) = P(T) + P(I) - P(TnI). Thus,
0.95 = 0.92 + 0.72 - P(TnI) ==> P(TnI) = 0.69. This means P(T/I) = P(T) - P(TnI) = 0.92 - 0.69 = 0.23, and P(I/T) = P(I) - P(TnI) = 0.72 - 0.69 = 0.03. So,
a)
House Probability
Nothing 0.05
Only television 0.23
Only internet 0.03
Both 0.69
b) P(internet but no television) = P(only internet) = 0.03
c) P(internet | there is television) = (By Bayes' Rule) P(TnI) / P(T) = 0.69 / 0.95 = 0.726 (rounded to 3 decimal points)
d) P(internet | there is no television) = (By Bayes' Rule) P(I/T) / P(T') = 0.03 / 0.08 = 0.375
e) From (c) and (d) ==> In Canada, it is (0.726/0.375 ≈ 2 ) twice more likely that if there's television in the household, then there is internet.
Step-by-step explanation:
The closest would be -7/10 or -1/2 because -3/5 is -.6 and the nearest fractions to -.6 is -7/10 and -1/2.
