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xxMikexx [17]
3 years ago
12

In a scale drawing a plane has a length of 35 centimeters. The actual length of the plane is 87.5 feet. What is the scale of the

drawing?
Mathematics
1 answer:
ICE Princess25 [194]3 years ago
3 0
If 35 cm  represent the length of the plane which is 87.5 ft of the actual plane length. let 1 cm be x ft. 
35 cm = 87.5 ft
1 cm = x ft
cross multiply this and the answer is 2.5 ft. Therefore, the scale drawing is 1 cm is 2.5 ft.
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The difference of the product of 3 and 6 minus the quotient of 6 divided by 2
Xelga [282]

Answer:

15

Step-by-step explanation:

3*6 - 6/2

18 - 3

15

4 0
3 years ago
Pls solve I need it solved rn show work urgent PLS*****
omeli [17]

Answer:

16. y=-5x-20; 17. y=6x+18, or factored y=6(x+3)

Step-by-step explanation:

Your slope is -5

y=-5x+b, solve for b by pluging the point (-3,-5) in for x and y

-5=-5(-3)+b, solve for b

-20=b, now rewrite the equation

y=-5x-20

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y=-5x+b, solve for b by pluging the point (-3,-0) in for x and y

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18=b, now rewrite the equation

y=6x+18, or factored y=6(x+3)

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3 years ago
3-4y=5x-6. The answer is (-5x^4-9)/4. Please explain how to get this.
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2 years ago
Find the general solution of the differential equation and check the result by differentiation. (Use C for the constant of integ
atroni [7]

Answer: y=Ce^(^3^t^{^9}^)

Step-by-step explanation:

Beginning with the first differential equation:

\frac{dy}{dt} =27t^8y

This differential equation is denoted as a separable differential equation due to us having the ability to separate the variables. Divide both sides by 'y' to get:

\frac{1}{y} \frac{dy}{dt} =27t^8

Multiply both sides by 'dt' to get:

\frac{1}{y}dy =27t^8dt

Integrate both sides. Both sides will produce an integration constant, but I will merge them together into a single integration constant on the right side:

\int\limits {\frac{1}{y} } \, dy=\int\limits {27t^8} \, dt

ln(y)=27(\frac{1}{9} t^9)+C

ln(y)=3t^9+C

We want to cancel the natural log in order to isolate our function 'y'. We can do this by using 'e' since it is the inverse of the natural log:

e^l^n^(^y^)=e^(^3^t^{^9} ^+^C^)

y=e^(^3^t^{^9} ^+^C^)

We can take out the 'C' of the exponential using a rule of exponents. Addition in an exponent can be broken up into a product of their bases:

y=e^(^3^t^{^9}^)e^C

The term e^C is just another constant, so with impunity, I can absorb everything into a single constant:

y=Ce^(^3^t^{^9}^)

To check the answer by differentiation, you require the chain rule. Differentiating an exponential gives back the exponential, but you must multiply by the derivative of the inside. We get:

\frac{d}{dx} (y)=\frac{d}{dx}(Ce^(^3^t^{^9}^))

\frac{dy}{dx} =(Ce^(^3^t^{^9}^))*\frac{d}{dx}(3t^9)

\frac{dy}{dx} =(Ce^(^3^t^{^9}^))*27t^8

Now check if the derivative equals the right side of the original differential equation:

(Ce^(^3^t^{^9}^))*27t^8=27t^8*y(t)

Ce^(^3^t^{^9}^)*27t^8=27t^8*Ce^(^3^t^{^9}^)

QED

I unfortunately do not have enough room for your second question. It is the exact same type of differential equation as the one solved above. The only difference is the fractional exponent, which would make the problem slightly more involved. If you ask your second question again on a different problem, I'd be glad to help you solve it.

7 0
2 years ago
The square root of a number is between 10 and 11. Which of these could be that number?
kaheart [24]
The answer would be 105, it's square root is approximately 10.2469 <span />
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3 years ago
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