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chubhunter [2.5K]
3 years ago
10

WILL GIVE BRAINLY IF CORRECT PLEASE HELP

Mathematics
2 answers:
balandron [24]3 years ago
6 0

Answer:

 7 ⋅ 2 ⋅ y   =   2 ⋅ 7 ⋅ y

  14 ⋅ y      =    14 ⋅ y

    14 ⋅ y = 14y

Step-by-step explanation:

Mnenie [13.5K]3 years ago
5 0

Answer:

Step-by-step explanation:

7(2y) = (7×2)y

Put the 7×2 in the box with parentheses around it. Put the y in the second box.

You might be interested in
Please solve this question <br>the answer is 45 degree ​
malfutka [58]

Answer:

∠ABC= 45°

Step-by-step explanation:

∠ABC= ∠BCD (alt. ∠s, AB//CD)

(2x +15)°= (3x)°

2x +15= 3x

3x-2x= 15 <em>(</em><em>-2x </em><em>on </em><em>both </em><em>sides)</em>

x= 15

Substituting the value of x:

∠ABC

= ∠BCD

= [3(15)]°

= 45°

7 0
2 years ago
What is the area of this figure? Enter your answer in the box.
Basile [38]
Luckily for us, the diagram already divided this figure into separate polygons. What I will be explaining is basically the addition of the areas of all the separate polygons. The area of the uppermost triangle is:

1/2 x b x h
= 1/2 x 20 x 8
(the base is 20, because in a parallelogram, opposite sides are congruent)
=10 x 8
= 80 in. squared

The next polygon we will be taking the area of is the parallelogram with the base length of 20 and the height of 16.

Area = b x h
= 20 x 16
= 320 in. squared

Now all we have left to do is add the two areas to obtain the total area.

Total Area = 320 + 80 = 400 in. squared


3 0
3 years ago
How does the numbers of zeros in the product of 8 and 5000 compare to the number of zeros in the factors?
o-na [289]
If product means to multiply than
5000*8= 40000
Answer: There is one more zero in the product.
6 0
3 years ago
On a particular map, 1 inch represents an actual distance of 2.5 miles. the actual area of a lake is 12 square miles. find the a
Anton [14]
We have that
scale factor=1 in/2.5 miles
<span>the actual area of a lake is 12 square miles

</span>we know that
[area on the map]=[scale factor]²*[area actual]
[area on the map]=[1/2.5]²*[12]-----> 1.92 in²

the answer is
1.92 in²

5 0
4 years ago
Evaluate: <br><br>6-(2/3)^2<br><br>A. 17/3<br>B. 52/3<br>C. 49/9<br>D. 50/9​
Komok [63]

Answer:

The correct answer is: "Option [D]".

Step-by-step explanation:

Hi student, let me help you out!

<u>....................................................................................................................................</u>

Let's use the acronym PEMDAS. With the help of this little acronym, we will not make mistakes in the Order of Operations!  :)

\dag\textsf{Acronym \: PEMDAS}

P=Parentheses,

E=Exponents,

M=Multiplication,

D=Division,

A=Addition,

S=Subtraction.

Now let's start evaluating our expression, which is \mathsf{6-(\cfrac{2}{3})^2}

According to PEMDAS, the operation that we should perform is "E-Exponents".

Notice that we have a fraction raised to a power. When this happens, we raise both the numerator (2 in this case) and the denominator (3 in this case) to that power, which is 2. After this we obtain  \mathsf{6-\cfrac{4}{9}}.

See, we raised both the numerator and the denominator to the power of 2.

Now what we should do is subtract fractions.

Note that 6 and -4/9 have unlike denominators. First, let's write 6 as a fraction: \mathrm{\cfrac{6}{1}-\cfrac{4}{9}}. Now let's multiply the denominator and the numerator of the first fraction times 9: \mathrm{\cfrac{54}{9}-\cfrac{4}{9}}.

See, now the fractions have the same denominator. All we should do now is subtract the numerators: \mathrm{\cfrac{50}{9}}.

∴, the answer is Option D.

Hope this helped you out, ask in comments if any queries arise.

Best Wishes!

\star\bigstar\underline{\overline{\overline{\underline{\textsf{Reach \: far. Aim \: high. Dream \: big.}}}}}\bigstar\star

\underline{\rule{300}{5}}

5 0
2 years ago
Read 2 more answers
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