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3 years ago

What is the value of x?

Mathematics

1 answer:

hjlf3 years ago

7 0

16 because the legth of TQ is the same as SR I hope thats right i checked with a ruler. :)

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Find all the zeros of the equation<br> -3x^4 + 27x^2 + 1200 = 0

guajiro [1.7K]

Answer:

$\displaystyle x=-5,\ x=5,\ x=4i,\ x=-4i$

Step-by-step explanation:

Biquadratic Equation

It's a fourth-degree equation where the terms of degree 1 and 3 are missing. It can be solved for the variable squared as if it was a second-degree equation, and then take the square root of the results

Our equation is

$\displaystyle -3x^4+27x^2+1200=0$

If we call $y=x^2$ , our equation becomes a second-degree equation

$\displaystyle -3y^2+27y+1200=0$

Dividing by -3

$\displaystyle y^2-9y-400=0$

Factoring

$\displaystyle (y-25)(y+16)=0$

It leads to these solutions

$\displaystyle y=25\ ,\ y=-16$

Taking back the change of variable, we have for the first solution

$\displaystyle x^2=25\Rightarrow x=-5,x=5$

Now for the second solution, we get imaginary (complex) values

$\displaystyle x^2=-16\Rightarrow x=4i,\ x=-4i$

Summarizing, the four solutions for x are

$\displaystyle x=-5,\ x=5,\ x=4i,\ x=-4i$

5 0

3 years ago

-5/8 Divided by -5/16

Arte-miy333 [17]

I hate dividing fractions but I think -2/16 off of my best hunch.

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3 years ago

A wheel of diameter 50.0 cm starts from rest and rotates with a constant angular acceleration of 2.00 rad/s^2. At the instant th

Kruka [31]

R = 25 cm = 0.25 m
α = 2.00 rad /s²
T(heta) = 4 π
ω = T(heta)/ t
ω = α t
α t = 4 π / t
t ² = 2 π
t = √ ( 2π ) = 2.5 s
ω = α t = 2 · 2.5 = 5 rad/s
v = ω r = 5 · 0.25 = 1.25 m/s
(1) a (rad) = ω² r = 25 · 0.25 = 6.25 m/s²
(2) a (rad) = v² / r = ( 1.25 )² / 0.25 = 0.15625 / 0.25 = 6.25 m/s²

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What is the value of the expression below? 5 + (-3)

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Answer: FAT SONIC SAYS.... THE ANSWER IS 125

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