Answer:
$487.2
Step-by-step explanation:
you multiply 14 and 12 then you get the answer of 168 and multiply that with $2.90 then you get the answer of $487.2.
Answer:
D: 4
Step-by-step explanation:
1. Solve the equation

2. Check

OK
Answer:
x = 9
y = 6
Step-by-step explanation:
3x+6i=27+yi
The real components have to be equal and the imaginary components have to be equal
3x = 27
divide by 3
3x/3 = 27/3
x=9
6i = yi
Divide by i
6 = y
Answer:

Step-by-step explanation:
Let's break it down:
In the sinusoidal function
:
represents Amplitude
represents a constant related to the Period
represents Phase Shift
represents Vertical Shift
To find Amplitude, divide the entire height of the function (from top to bottom) by two, or find the vertical distance between the horizontal line of symmetry and the highest/lowest point of the wave. In this case, Amplitude is 2.
To find
, use
, where
is the period of the function. To find the period, count the horizontal distance of the length of one complete cycle. In this case, period is
and therefore
.
To find Phase Shift, find the horizontal shift from the parent function
. In this case, there is no phase shift.
To find Vertical Shift, find the vertical shift from the parent function
. In this case, vertical shift is -1.
Thus, we've found:
Substituting these values into
, we get:
