The answer is C. (2jk)^-2
Answer:
1 : 30
Step-by-step explanation:
300mm:9m
We need to change the meters to mm
1 meter is 1000 mm
so 9 m is 9000 mm
300mm:9000mm
Divide both sides by 300
300mm/300 : 9000/300
1 : 30
Answer:
Does not factor; domain = -∞<x<∞, range = f(x) ≤ 2.
Step-by-step explanation:
Assuming your end goal is to factor the polynomial
If we use the guess and check method we can see that there is no way to factor this polynomial.
However, if you are looking for a domain and range we can graph it on a graphing calculator. Just by looking at the graph, we can see that the domain is all real numbers, or -∞<x<∞, and the range is f(x) ≤ 2.
I hope this helped!
Answer:
93.53m.
Step-by-step explanation:
.
Is RS perpendicular to DF? Select Yes or No for each statement. R (6, −2), S (−1, 8), D (−1, 11), and F (11 ,4) R (1, 3), S (4,7
guajiro [1.7K]
I'll do the first one to get you started.
Find the slope of the line between R (6,-2) and S (-1,8) to get
m = (y2-y1)/(x2-x1)
m = (8-(-2))/(-1-6)
m = (8+2)/(-1-6)
m = 10/(-7)
m = -10/7
The slope of line RS is -10/7
Next, we find the slope of line DF
m = (y2 - y1)/(x2 - x1)
m = (4-11)/(11-(-1))
m = (4-11)/(11+1)
m = -7/12
From here, we multiply the two slope values
(slope of RS)*(slope of DF) = (-10/7)*(-7/12)
(slope of RS)*(slope of DF) = (-10*(-7))/(7*12)
(slope of RS)*(slope of DF) = 10/12
(slope of RS)*(slope of DF) = 5/6
Because the result is not -1, this means we do not have perpendicular lines here. Any pair of perpendicular lines always has their slopes multiply to -1. This is assuming neither line is vertical.
I'll let you do the two other ones. Let me know what you get so I can check your work.
