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3 years ago

How to find area and perimeter of a rectangle with the numbers 4√6cm and 5√6cm

1 answer:

4 0

You need to calculate what those numbers are first.
4√6cm =9.79
5√6cm= 12.24
add them together
21.96
multiply by 4
87.86

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2 years ago

The equation $a^7xy-a^6y-a^5x=a^4(b^4-1)$ is equivalent to the equation $(a^mx-a^n)(a^py-a^2)=a^4b^4$ for some integers $m$, $n$

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Let simplify the equations $a^7xy-a^6y-a^5x=a^4(b^4-1)$ and $(a^mx-a^n)(a^py-a^2)=a^4b^4$ :

1) $a^7xy-a^6y-a^5x+a^4=a^4b^4$

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2) $a^{m+p}xy-a^{n+p}y-a^{m+2}x+a^{n+2}=a^4b^4$ .

Equate the coefficients:

 $xy: m+p=7 \\ y: n+p=6 \\ x: m+2=5 \\ 1: n+2=4$ .
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