Here where you label the y and slope
Answer:
For f(x) to be differentiable at 2, k = 5.
Step-by-step explanation:
For f(x) to be differentiable at x = 2, f(x) has to be continuous at 2.
For f(x) to be continuous at 2, the limit of f(2 – h) = f(2) = f(2 + h) as h tends to 0.
Now,
f(2 – h) = 2(2 – h) + 1 = 4 – 2h + 1 = 5 – 2h.
As h tends to 0, lim (5 – 2h) = 5
Also
f(2 + h) = 3(2 + h) – 1 = 6 + 3h – 1 = 5 + 3h
As h tends to 0, lim (5 + 3h) = 5.
So, for f(2) to be continuous k = 5
Answer:
B: 60
Step-by-step explanation:
f(x)= 5x+10, if x=10
f(10)=5(10)+10
5(10)+10=60
f(10)=60
Answer:
-2g -10
Step-by-step explanation:
On simplifing this expression we get,
-2(g+5)
=> -2g + (-10)
=> -2g - 10
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