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gizmo_the_mogwai [7]
3 years ago
13

(5,-4) 4 Position Pairs of Rational Numbers on the Coordinate Plane

Mathematics
1 answer:
Paraphin [41]3 years ago
8 0

Answer:

The Fourth box, aka, the bottom right.

Step-by-step explanation:

There is 4 boxes. Top right for 2 positive pairs, top left for 1 negative, one positive pair, bottom left Both negative pairs, and bottom right, One positive, one negative.

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Inverse function of y = -2x3+1
Ymorist [56]
The answer to your question is y=-5
6 0
3 years ago
Which of the following statements are true?
Eduardwww [97]

Answer:

B, C

Step-by-step explanation:

Consider all options:

A. The graph of the function f(x)=\dfrac{1}{2}\sqrt[3]{x} is vertically shrunk by a factor \frac{1}{2} the graph of the function f(x)=\sqrt[3]{x}, so the domain and the range of both functions are the same. This option is false.

B.  The graph of the function f(x)=\dfrac{1}{2}\sqrt[3]{x} is vertically shrunk by a factor \frac{1}{2} the graph of the function f(x)=\sqrt[3]{x}, so the domain and the range of both functions are the same. This option is true.

C. The graph of the function f(x)=\dfrac{1}{2}\sqrt[3]{(x-2)} is translated 2 units to the right and vertically shrunk by a factor \frac{1}{2} the graph of the function f(x)=\sqrt[3]{x}, so their graphs are similar except the first graph is shifted right and shrunk vertically by a factor of \frac{1}{2}.. This option is true.

D. The function f(x)=\dfrac{1}{2}\sqrt{x} has the domain and the range all non-negative real values. The function  f(x)=\sqrt[3]{x} has the domain and the range all real values. So this option is false.

3 0
4 years ago
Can anyone help me. greatly appreciate
mixas84 [53]
I can’t really see it get a clear picture
7 0
3 years ago
Find the midpoint of the line segment whose endpoints are (-2, 5) and (4, -9).Find the midpoint of the line segment whose endpoi
jek_recluse [69]

Answer:

The midpoint is (1,-2)

Step-by-step explanation:

we know that

The formula to calculate the midpoint between two points is equal to

M(\frac{x1+x2}{2},\frac{y1+y2}{2})

we have

(x1,y1)=(-2,5)

(x2,y2)=(4,-9)

substitute

M(\frac{-2+4}{2},\frac{5-9}{2})

M(1,-2)

8 0
3 years ago
A fruit company delivers its fruit in two types of boxes: large and small. A delivery of
Tema [17]

Answer:

Small box weighs 13.75 kg & large box weighs 15.75 kg

Step-by-step explanation:

We can write 2 simultaneous equation and solve for weight of each box.

<em>Let weight of large box be l and small box be s.</em>

<em />

"<u>3 large boxes and  5 small boxes has a total weight of  116 kilograms</u>":

3l+5s=116

and

"<u>9 large boxes and  7 small boxes has a total weight of  238 kilograms</u>":

9l+7s=238

<em>Now we can solve for l in the 1st equation and put it into 2nd equation and get s:</em>

<em>3l+5s=116\\3l=116-5s\\l=\frac{116-5s}{3}</em>

<em>now,</em>

<em>9l+7s=238\\9(\frac{116-5s}{3})+7s=238\\3(116-5s)+7s=238\\348-15s+7s=238\\348-238=15s-7s\\110=8s\\s=\frac{110}{8}=13.75</em>

<em />

<em>now we plug in 13.75 into s into equation of l to find s:</em>

<em>l=\frac{116-5s}{3}\\l=\frac{116-5(13.75)}{3}\\l=15.75</em>

5 0
3 years ago
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