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gizmo_the_mogwai [7]
3 years ago
13

(5,-4) 4 Position Pairs of Rational Numbers on the Coordinate Plane

Mathematics
1 answer:
Paraphin [41]3 years ago
8 0

Answer:

The Fourth box, aka, the bottom right.

Step-by-step explanation:

There is 4 boxes. Top right for 2 positive pairs, top left for 1 negative, one positive pair, bottom left Both negative pairs, and bottom right, One positive, one negative.

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-1/2 because slope is the rise over the run. If you count on the grid from one point on the line to another you go up one and 2 to the left meaning the slope is 1/2, buttttt when the line decreases going to the right, it has a negative slope so you just add a - sign in front
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2 years ago
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Find the distance between the points with coordinates (5, 7) and (-3, 1)
Bess [88]
You would use the function root(Xsub2-Xsub1)^2+(Ysub2-Ysub1)^2.

Now plug in your numbers.

This gives you root(7-1)^2+(5-(-3))^2.

Simplify to root(6)^2+(8)^2. Simplify again to root36+64.

Simplify one more time to root 100. now solve.

Your answer is 10.
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3 years ago
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Katena32 [7]

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3 years ago
Need pre-cal help. Will mark best answer brainliest
OlgaM077 [116]

so, let's keep in mind that

\bf \begin{array}{|c|ll} \cline{1-1} \textit{a\% of b}\\ \cline{1-1} \\ \left( \cfrac{a}{100} \right)\cdot b \\\\ \cline{1-1} \end{array}

so let's make a quick table of those solutions, say A, B, C solutions with x,y,z liters of acid, with an acidity of 0.25, 0.40 and 0.60 respectively.


\bf \begin{array}{lcccl} &\stackrel{solution}{quantity}&\stackrel{\textit{\% of }}{amount}&\stackrel{\textit{liters of }}{amount}\\ \cline{2-4}&\\ A&x&0.25&0.25x\\ B&y&0.40&0.4y\\ C&z&0.60&0.6z\\ \cline{2-4}&\\ mixture&78&0.45&35.1 \end{array} \\\\\\ \begin{cases} x+y+z=78\\ 0.25x+0.4y+0.6z=35.1 \end{cases}


we know she's using "z" liters and those are 3 times as much as "y" liters, so z = 3y.


\bf \begin{cases} x+y+3y=78\\ x+4y=78\\[-0.5em] \hrulefill\\ 0.25x+0.4y+0.6(3y)=35.1\\ 0.25x+0.4y=1.8y=35.1\\ 0.25x+2.2y=35.1 \end{cases}\implies \begin{cases} x+4y=78\\\\ 0.25x+2.2y=35.1 \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ x+4y=78\implies \boxed{x}=78-4y \\\\\\ \stackrel{\textit{using substitution on the 2nd equation}}{0.25\left( \boxed{78-4y} \right)+2.2y=35.1}\implies 19.5-y+2.2y=35.1


\bf 1.2y=15.6\implies y=\cfrac{15.6}{1.2}\implies \blacktriangleright y=13 \blacktriangleleft \\\\\\ x=78-4y\implies x=78-4(13)\implies \blacktriangleright x=26 \blacktriangleleft \\\\\\ z=3y\implies z=3(13)\implies \blacktriangleright z=39 \blacktriangleleft \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill \stackrel{25\%}{26}\qquad \stackrel{40\%}{13}\qquad \stackrel{60\%}{39}~\hfill

5 0
3 years ago
How many complex roots does the polynomial equation have?<br><br> 3x5−2x+1=0
dmitriy555 [2]

Answer : The given polynomial equation can have 0,2 or 4 complex roots.

Explanation:-

Given polynomial equation is 3x^5-2x+1=0 which is a polynomial of degree 5.

We know that the complex roots always occur in pair ,therefore the number of complex roots in any polynomial must be an even number but less than equal  to the degree of polynomial.

Thus, the given polynomial equation has 4 complex roots.

3 0
3 years ago
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