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MArishka [77]
2 years ago
6

the area of the shaded portion of the diagram below is equal to half the total area. find the area of the unshaded part.​

Mathematics
1 answer:
BabaBlast [244]2 years ago
4 0

Answer:

27 cm^2

Step-by-step explanation:

Suppose the line divided the triangle into two equal triangles

The side lengths for unshaded area is 6 9 10

To find the area of a triangle all we do is multiply height with base and that divided by two

9×6÷2 = 27 cm^2

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There are 10 multiple choice questions in an examination. first 4 have 5 choices each and remaining have 4 choices each. how man
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2560000 sequences of answers are possible.

<em><u>Explanation</u></em>

Total number of questions = 10

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3 years ago
Which expression is equivalent to RootIndex 3 StartRoot 32 x Superscript 8 Baseline y Superscript 10 Baseline EndRoot?
evablogger [386]

Answer:

The equivalent expression to the given expression is \sqrt[3]{32x^8y^{10}}=2x^2y^3\sqrt[3]{4x^2y}

Step-by-step explanation:

The given expression is \sqrt[3]{32x^8y^{10}}

To find the equivalent expression:

\sqrt[3]{32x^8y^{10}}=(32x^8y^{10})^{\frac{1}{3}}

We may write the above expression as below:

=(32^{\frac{1}{3}})((x^8)^{\frac{1}{3}})((y^{10})^{\frac{1}{3}})

=(2)((4)^{\frac{1}{3}})(x^6)\times (x^2)(x^{\frac{2}{3}})(y^3)(y^{\frac{1}{3}}) (using square root properties)

=(2\sqrt[3]{4})(x^2\sqrt[3]{x^2})(y^3\sqrt[3]{y}) (combining the like terms and doing multiplication )

=2x^2y^3\sqrt[3]{4x^2y}

Therefore \sqrt[3]{32x^8y^{10}}=2x^2y^3\sqrt[3]{4x^2y}

Therefore the equivalent expression to the given expression is \sqrt[3]{32x^8y^{10}}=2x^2y^3\sqrt[3]{4x^2y}

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