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son4ous [18]
3 years ago
11

If f(x) = 4x + 8 and g(x) = (x+4, what is (fºg)(12)?

Mathematics
1 answer:
svetlana [45]3 years ago
4 0

Answer:

72

Step-by-step explanation:

f(x) = 4x+8\\g(x) = x + 4\\\\1. f(g(x)) = 4(x+4) + 8\\2. f(g(x)) = 4x + 16 + 8\\3. f(g(x))=4x + 24\\\\4. f(g(12)) = 4(12) + 24\\5. f(g(12)) = 48 + 24 = 72\\

To do these, you have to place the entire function inside the parent function's variables.

You are inputting the value of the function g(x) into f(x)

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Which of the following represents the formula that could be used to find the height of the cone
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If you know the volume then:
(3 * Cone Volume) / (PI * radius^2) = height

 
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Canada has a population that is about 1/10 as large as the United States. If Canada's population is about 32 millon, about how m
bezimeni [28]
Since 32 mil is 1/10 of the US pop, multiply 32 mil by 10 so you get the 10/10 aka the whole US pop. That means it would be 320,000,000. All you do is add a zero to 32 mil since you multiply by 10. 32 mil originally had 6 zeros. After multiplying, you have 7 zeros.
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A bicycle lock has a four-digit code. The possible digits, 0 What is the probability that the lock code will begin with
nika2105 [10]

Answer:

0.1-0.6

Step-by-step explanation:

First let's find the number of the elements in the sample space, that is the total number of codes that can be produced.

The first digit is any of {0, 1, 2...,9}, that is 10 possibilities

the second digit is any of the remaining 9, after having picked one. 

and so on...

so in total there are 10*9*8*7 = 5040 codes.

a. What is the probability that the lock code will begin with 5?

Lets fix the first number as 5. Then there are 9 possibilities for the second digit, 8 for the third on and 7 for the last digit.

Thus, there are 1*9*8*7=504 codes which start with 5.

so 

P(first digit is five)=

b. What is the probability that the lock code will not contain the number 0? 

from the set {0, 1, 2...., } we exclude 0, and we are left with {1, 2, ...9}

from which we can form in total 9*8*7*6 codes which do not contain 0.

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Answer:

0.1 ; 0.6

8 0
3 years ago
Read 2 more answers
Please help me !!!!!!
Nezavi [6.7K]

Answer:

A

Step-by-step explanation:

Hope it helps!

5 0
2 years ago
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Write an equation of the circle that has a diameter with endpoints (12, 3) and<br> (-18,3).
Mademuasel [1]

The equation of the circle that has a diameter with endpoints (12, 3) and(-18,3) is x² + y² + 6x - 6y - 207 = 0

<h3>Coordinates of center of circle</h3>

Since the endpoints of the diameter are (x₁, y₁) = (12,3) and (x₂, y₂) = (-18,3), the coordinates of the center of the circle are the midpoints of the diameter. So, the midpoints are

  • x = (x₁ + x₂)/2 = (12 + (-18))/2 = (12 - 18)/2 = -6/2 = -3 and
  • y = (y₁ + y₂)/2 = (3 + 3)/2 = 6/2 = 3.

So, the coordinates of the center of the circle are (-3, 3)

<h3>The radius of the circle</h3>

The radius of the circle r = √[(x₁ - h)² + (y₁ - k)²] where

  • (x₁, y₁) = coordinates of end of diameter = (12, 3) and
  • (h, k) = coordinates of center of circle = (-3, 3)

So, substituting the values of the variables into r, we have

r = √[(x₁ - h)² + (y₁ - k)²]

r = √[(12 - (-3))² + (3 - 3)²]

r = √[(12 + 3)² + 0²]

r = √[15² + 0²]

r = √15²

r = 15

<h3>The equation of the circle</h3>

The equation of a circle with center (h,k) is given by

(x - h)² + (y - k)² = r² where r = radius of circle.

Substituting the values of the variables into the equation, we have

(x - h)² + (y - k)² = r²

(x - (-3))² + (y - 3)² = 15²

(x + 3)² + (y - 3)² = 15²

x² + 6x + 9 + y² - 6y + 9 = 225

x² + 6x + y² - 6y + 9 + 9 - 225 = 0

x² + y² + 6x - 6y - 207 = 0

The equation of the circle that has a diameter with endpoints (12, 3) and(-18,3) is x² + y² + 6x - 6y - 207 = 0

Learn more about equation of a circle here:

brainly.com/question/18435467

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