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Svetach [21]
3 years ago
15

Someone please help me with these 2 questions I will mark brainlist!!!!

Mathematics
1 answer:
Tamiku [17]3 years ago
8 0
ANSWER for the first one:
A=a+b/2*h
A= 4.5+9/2*6
A= 40.5 cm2

ANSWER for the second one:
9*3= 27
3*3= 9
9*3= 27
A= 63 cm2
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If 3x − (7 − x) = 29, find the value of 6x.
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Answer:

54

Step-by-step explanation:

3x -(7-x) = 29       remove the parens

3x - 7 + x = 29     simplify

4x -7 = 29            add 7 to both sides of the equation

4x = 36            divide by

x = 9

then 6x = 6 * 9 = 54

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2 years ago
A recipe for a cake calls for 3 cups of flour. Tyler accidentally put in 4 cups. How many
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He put in 1 extra cup because the recipe only needed 3. 4-3=1.
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Use the exponential decay​ model, Upper A equals Upper A 0 e Superscript kt​, to solve the following. The​ half-life of a certai
Akimi4 [234]

Answer:

It will take 7 years ( approx )

Step-by-step explanation:

Given equation that shows the amount of the substance after t years,

A=A_0 e^{kt}

Where,

A_0 = Initial amount of the substance,

If the half life of the substance is 19 years,

Then if t = 19, amount of the substance = \frac{A_0}{2},

i.e.

\frac{A_0}{2}=A_0 e^{19k}

\frac{1}{2} = e^{19k}

0.5 = e^{19k}

Taking ln both sides,

\ln(0.5) = \ln(e^{19k})

\ln(0.5) = 19k

\implies k = \frac{\ln(0.5)}{19}\approx -0.03648

Now, if the substance to decay to 78​% of its original​ amount,

Then A=78\% \text{ of }A_0 =\frac{78A_0}{100}=0.78 A_0

0.78 A_0=A_0 e^{-0.03648t}

0.78 = e^{-0.03648t}

Again taking ln both sides,

\ln(0.78) = -0.03648t

-0.24846=-0.03648t

\implies t = \frac{0.24846}{0.03648}=6.81085\approx 7

Hence, approximately the substance would be 78% of its initial value after 7 years.

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3 years ago
The graph of y=e* is transformed as shown in the graph below. Which equation represents the transformed
butalik [34]

Answer:

what are the answers

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2 years ago
What number should be added to both sides of the equation to complete the square?<br> x^2+ 8x = 4
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16

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