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AveGali [126]
2 years ago
15

What is the correct ratio?

Mathematics
1 answer:
damaskus [11]2 years ago
5 0

Answer:

A: 9/40

Step-by-step explanation:

Hopefully this helps!

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Please help asap. Thank you! :)
Kruka [31]

When he cubed ,

Result is x³

On further squaring x³, he got = (x³)²

{x}^{6}

<h3>Therefore, k = 6</h3>

7 0
2 years ago
Solve for XX. Assume XX is a 2×22×2 matrix and II denotes the 2×22×2 identity matrix. Do not use decimal numbers in your answer.
sveticcg [70]

The question is incomplete. The complete question is as follows:

Solve for X. Assume X is a 2x2 matrix and I denotes the 2x2 identity matrix. Do not use decimal numbers in your answer. If there are fractions, leave them unevaluated.

\left[\begin{array}{cc}2&8\\-6&-9\end{array}\right]· X·\left[\begin{array}{ccc}9&-3\\7&-6\end{array}\right] =<em>I</em>.

First, we have to identify the matrix <em>I. </em>As it was said, the matrix is the identiy matrix, which means

<em>I</em> = \left[\begin{array}{ccc}1&0\\0&1\end{array}\right]

So, \left[\begin{array}{cc}2&8\\-6&-9\end{array}\right]· X·\left[\begin{array}{ccc}9&-3\\7&-6\end{array}\right] =  \left[\begin{array}{ccc}1&0\\0&1\end{array}\right]

Isolating the X, we have

X·\left[\begin{array}{ccc}9&-3\\7&-6\end{array}\right]= \left[\begin{array}{cc}2&8\\-6&-9\end{array}\right] -  \left[\begin{array}{ccc}1&0\\0&1\end{array}\right]

Resolving:

X·\left[\begin{array}{ccc}9&-3\\7&-6\end{array}\right]= \left[\begin{array}{ccc}2-1&8-0\\-6-0&-9-1\end{array}\right]

X·\left[\begin{array}{ccc}9&-3\\7&-6\end{array}\right]=\left[\begin{array}{ccc}1&8\\-6&-10\end{array}\right]

Now, we have a problem similar to A.X=B. To solve it and because we don't divide matrices, we do X=A⁻¹·B. In this case,

X=\left[\begin{array}{ccc}9&-3\\7&-6\end{array}\right]⁻¹·\left[\begin{array}{ccc}1&8\\-6&-10\end{array}\right]

Now, a matrix with index -1 is called Inverse Matrix and is calculated as: A . A⁻¹ = I.

So,

\left[\begin{array}{ccc}9&-3\\7&-6\end{array}\right]·\left[\begin{array}{ccc}a&b\\c&d\end{array}\right]=\left[\begin{array}{ccc}1&0\\0&1\end{array}\right]

9a - 3b = 1

7a - 6b = 0

9c - 3d = 0

7c - 6d = 1

Resolving these equations, we have a=\frac{2}{11}; b=\frac{7}{33}; c=\frac{-1}{11} and d=\frac{-3}{11}. Substituting:

X= \left[\begin{array}{ccc}\frac{2}{11} &\frac{-1}{11} \\\frac{7}{33}&\frac{-3}{11}  \end{array}\right]·\left[\begin{array}{ccc}1&8\\-6&-10\end{array}\right]

Multiplying the matrices, we have

X=\left[\begin{array}{ccc}\frac{8}{11} &\frac{26}{11} \\\frac{39}{11}&\frac{198}{11}  \end{array}\right]

6 0
3 years ago
Which triangle is a right triangle?
iren [92.7K]

Answer:

A right triangle is always 90 degrees.

Step-by-step explanation:

4 0
3 years ago
12.2​z ​+ 19.4 = -2.7​z​ + 93.9
Digiron [165]

Answer:

z=5

Step-by-step explanation:

12.2z​+ 19.4 = -2.7​z​ + 93.9

14.9z=74.5

z=5

3 0
3 years ago
Read 2 more answers
Calculați aplicând distributivitatea înmulțirii fata de adunare și de scădere
solmaris [256]

Răspuns:

7/5;

2 întreg 5/12

Explicație pas cu pas:

6/7 × (2 numere întregi și 5 / 6-1 numere întregi și 1/5)

6/7 * (2 5/6 - 1 1/5)

6/7 * (17/6 - 6/5)

6/7 * (85 - 36) / 30

7/7 * 49/30

1/1 * 7/5

= 7/5

2.)

5/8 × 1 întreg și 2/3 + 11/5

5/8 * (1 2/3 + 11/5)

5/8 * (5/3 + 11/5)

5/8 * (25 + 33) / 15

5/8 * 58/15

1/8 * 58/3

= 58/24

= 2 întreg 10/24

= 2 întreg 5/12

4 0
2 years ago
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