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Alik [6]
3 years ago
12

If 2x+ 3y = 55 and 4x= y+ 47, find x − y. Can you please explain with some details?

Mathematics
1 answer:
balu736 [363]3 years ago
8 0
4x=y+47, we can subtract 47 from both sides to get:
4x-47=y, now we know what y equals in terms of x, so we can substitute that in to the other equation:
2x+3y=55 becomes 2x+3*(4x-47)=55 which becomes:
2x+12x-141=55 which becomes 14x-141=55 and we can add 141 to both sides:
14x=196, divide 14 by both sides, we get x=14, which we can substitute back into the y=equation:
4x-47=y becomes 14*4-47=y which becomes y=9
x=14, y=9
x-y=14-9=5
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<u>Answer</u>:

3003 number of 5-member chess teams can be chosen from 15 interested players.

<u>Step-by-step explanation:</u>

Given:

Number of the interested players =  15

To Find:

Number of 5-member chess teams that can be chosen = ?

Solution:

Combinations are a way to calculate the total outcomes of an event where order of the outcomes does not matter. To calculate combinations, we will use the formulanCr = \frac{n!}{r!(n - r)!}

where

n represents the total number of items,

r represents the number of items being chosen at a time.

Now  we have n = 15 and r = 5

Substituting the values,

15C_5 = \frac{15!}{5!(15- 5)!}

15C_5 = \frac{15!}{5!(10)!}

15C_5 = \frac{15!}{5!(10)!}

15C_5 = \frac{15\times \times 14 \times 13 \times 12 \times 11 \times 10 \times 9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1 }{5 \times 4 \times 3 \times 2 \times 1(10 \times 9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1)}

15C_5 = \frac{15\times \times 14 \times 13 \times 12 \times 11}{(5 \times 4 \times 3 \times 2 \times 1)}

15C_5 = \frac{360360}{120}

15C_5 = 3003

7 0
3 years ago
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5 0
3 years ago
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3 years ago
What is 12(18)&gt;8+34-98=
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Answer:

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TRUE

Step-by-step explanation:

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