Answer:
k is greater than negative 2 or negative 2 is less than k.
Step-by-step explanation:
2k-8>-12
+8 +8
2k>-4
÷2 ÷2
k>-2
k is greater than negative 2
Answer:
so the answer is I don't know
7/g This is the correct answer to your problem
Answer:
The average value of over the interval is .
Step-by-step explanation:
Let suppose that function is continuous and integrable in the given intervals, by integral definition of average we have that:
(1)
(2)
By Fundamental Theorems of Calculus we expand both expressions:
(1b)
(2b)
We obtain the average value of over the interval by algebraic handling:
The average value of over the interval is .
Find common denominators. 10 is the common denominator. Multiply 2 to numerator and denominator of -3/5
(-3/5)(2/2) = -6/10
x + 1/10 = -6/10
Isolate the x. Subtract 1/10 from both sides
x + 1/10 (-1/10) = -6/10 (-1/10)
x = -6/10 - 1/10
x = -7/10
-7/10 is your answer for x
hope this helps