Answer:
roots=(5±sqrt(33))/4
Step-by-step explanation:
roots=(-b±sqrt(b^2-4ac))/2a
roots=(-(-5)±sqrt(25+8))/(2*2)
roots=(5±sqrt(33))/4
roots=(5+sqrt(33))/4 and (5-sqrt(33))/4
The range of a function is the set of all values that it can take when its independent variable takes values on the domain.
On the other hand, the range of a function is the domain of its inverse function, if that inverse exists, and vice-versa: the domain of a function is the range of its inverse function, if that inverse exists.
In the case of the given equation:

The inverse function exists since the function is linear, and it can be found by isolating <em>x</em>:

If the range of the original function is the set given by the number {
Answer: 2
The equivalent ratios are 1:2 and 5:10
Step-by-step explanation:
Answer:
27
Step-by-step explanation:
Evaluate the
= 3
Since
= 81
We are noe left to evaluate (3)³ = 27
Answer:
We need to solve the each side as though it is the hypotenuse:
AB: 6^2 + 5^2 = 61 => 7.81
BC: 8^2 + 5^2 = 89 => 9.43
CD: 4^2 + 3^2 = 25 => 5
DE: 4^2 + 2^2 = 20 => 4.47
EA: 2^2 + 5^2 = 29 => 5.39
Total 32.10 Units
Step-by-step explanation:
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