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elixir [45]
3 years ago
6

5x - 43 + 3x - 33 = 180

Mathematics
2 answers:
Salsk061 [2.6K]3 years ago
3 0

Answer:

x = 32

Step-by-step explanation:

5x - 43 + 3x - 33 = 180

Combine like terms

8x -76 = 180

Add 76 to each side

8x -76+76 = 180+76

8x =256

Divide each side by 8

8x/8 = 256/8

x = 32

alex41 [277]3 years ago
3 0

Steps to solve:

5x - 43 + 3x - 33 = 180

~Combine Like Terms

(5x + 3x) + (-43 - 33) = 180

~Simplify

8x - 76 = 180

~Add 76 to both sides

8x - 76 + 76 = 180 + 76

~Simplify

8x = 256

~Divide 8 to both sides

8x/8 = 256/8

~Simplify

x = 32

Best of Luck!

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2x -2x = 0

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Step-by-step explanation:

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6. The diagram on the right shows the cross-section of a cylindrical pipe with water lying in the bottom. a) If the maximum dept
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Step-by-step explanation:

Let's Draw a line from the center of the circle to one of the ends of the chord (water surface) and another to the point at greatest depth on your paper. A right-angled triangle is formed too. The Length of side to the water-surface is 5 cm, the hospot is 7 cm.

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44.4°, so the angle subtended at the center of the circle by the water surface is roughly 88.8°

The area shaded will then be the area of the sector minus the area of the triangle above the water in your diagram.

Shaded area 88.8/360*area of circle - ½*7*788.8°

= 88.8/360*π*7² - 24.5*sin 88.8°

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6 0
1 year ago
What is each power of i with its multiplicative inverse.
pentagon [3]

Answer:

1) multiplicative inverse of i = -i

2) Multiplicative inverse of i^2 = -1

3) Multiplicative inverse of i^3 = i

4) Multiplicative inverse of i^4 = 1

Step-by-step explanation:

We have to find multiplicative inverse of each of the following.

1) i

The multiplicative inverse is 1/i

if i is in the denominator we find their conjugate

=1/i * i/i\\=i/i^2\\=We\,\, know\,\, that\,\, i^2 = -1\\=i/(-1)\\= -i

So, multiplicative inverse of i = -i

2) i^2

The multiplicative inverse is 1/i^2

We know that i^2 = -1

1/-1 = -1

so, Multiplicative inverse of i^2 = -1

3) i^3

The multiplicative inverse is 1/i^3

We know that i^2 = -1

and i^3 = i.i^2

1/i^3\\=1/i.i^2 \\=1/i(-1)\\=-1/i * i/i\\=-i/i^2\\= -i/-1\\= i

so, Multiplicative inverse of i^3 = i

4) i^4

The multiplicative inverse is 1/i^4

We know that i^2 = -1

and i^4 = i^2.i^2

=1/i^2.i^2\\=1/(-1)(-1)\\=1/1\\=1

so, Multiplicative inverse of i^4 = 1

3 0
3 years ago
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