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Sholpan [36]
3 years ago
15

Plsss help if u can 6th grade math

Mathematics
2 answers:
kolbaska11 [484]3 years ago
4 0

Answer:

a

Step-by-step explanation:

a

gregori [183]3 years ago
3 0
The answer is A I believe
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Read 2 more answers
Part A. Write an equation of a line that is perpendicular to the line y = 2/3x + 5 and passes through the point (4, 0).
fenix001 [56]

Answer:

y = -\frac{3}{2}x+6

Step-by-step explanation:

Given:

The given equation of the line y = \frac{2}{3} x + 5 that passes through the point (4, 0).

Part A.

The equation of the line.

y=mx+c-----------(1)

Where:

m = Slope of the line

c = y-intercept

The given equation of the line.

y = \frac{2}{3} x + 5

Comparing the given equation with equation 1.

The slope of the line is m=\frac{2}{3} and y-intercept c = 5

We know that the slope of the perpendicular line is (-\frac{1}{m}).

So the slope of the perpendicular line is (m=-\frac{1}{\frac{2}{3}}=-\frac{3}{2}).

Using point slope formula we write the equation of the perpendicular line that passes through the point (4, 0).

y-y_{1} = m(x-x_{1}

Now we substitute the slope of the perpendicular line m=-\frac{3}{2} and y_{1} = 0, x_{1}=4 from point (4, 0) in above equation.  

y-0 = -\frac{3}{2}(x-4)

y = -\frac{3}{2}x-(-\frac{3}{2}\times 4)

y = -\frac{3}{2}x-(-3\times 2)

y = -\frac{3}{2}x-(-6)

y = -\frac{3}{2}x+6

Therefore the perpendicular line equation is y = -\frac{3}{2}x+6.

Part B.

1. The slope of the perpendicular line is m=-\frac{3}{2}.

2. The y-intercept of the perpendicular line is 6.

3. The equation of the line y = -\frac{3}{2}x+6 is perpendicular to the equation of line y = \frac{2}{3} x + 5.

6 0
3 years ago
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