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Greeley [361]
3 years ago
9

How do I solve 5x/6=-8 to get the answer

Mathematics
1 answer:
Daniel [21]3 years ago
5 0

Answer:

Download photo math

Step-by-step explanation:

You might be interested in
A function f defined by f(x) = x² + px + q is such that f(3) = 6 and f¹(3) = 0. Find the value of q.
CaHeK987 [17]

Answer:

q = 15

Step-by-step explanation:

Given

f(x) = x² + px + q , then

f(3) = 3² + 3p + q = 6 , that is

9 + 3p + q = 6 ( subtract 9 from both sides )

3p + q = - 3 → (1)

---------------------------------------

f'(x) = 2x + p , then

f'(3) = 2(3) + p = 0, that is

6 + p = 0 ( subtract 6 from both sides )

p = - 6

Substitute p = - 6 into (1)

3(- 6) + q = - 3

- 18 + q = - 3 ( add 18 to both sides )

q = 15

5 0
3 years ago
The heights of men in a certain population follow a normal distribution with mean 69.7 inches and standard deviation 2.8 inches.
Mama L [17]

Answer:

a) P(Y > 76) = 0.0122

b) i) P(both of them will be more than 76 inches tall) = 0.00015

   ii) P(Y > 76) = 0.0007

Step-by-step explanation:

Given - The heights of men in a certain population follow a normal distribution with mean 69.7 inches and standard deviation 2.8 inches.

To find - (a) If a man is chosen at random from the population, find

                    the probability that he will be more than 76 inches tall.

              (b) If two men are chosen at random from the population, find

                    the probability that

                    (i) both of them will be more than 76 inches tall;

                    (ii) their mean height will be more than 76 inches.

Proof -

a)

P(Y > 76) = P(Y - mean > 76 - mean)

                 = P( \frac{( Y- mean)}{S.D}) > \frac{( 76- mean)}{S.D})

                 = P(Z >  \frac{( 76- mean)}{S.D})

                 = P(Z > \frac{76 - 69.7}{2.8})

                 = P(Z > 2.25)

                 = 1 - P(Z  ≤ 2.25)

                 = 0.0122

⇒P(Y > 76) = 0.0122

b)

(i)

P(both of them will be more than 76 inches tall) = (0.0122)²

                                                                           = 0.00015

⇒P(both of them will be more than 76 inches tall) = 0.00015

(ii)

Given that,

Mean = 69.7,

\frac{S.D}{\sqrt{N} } = 1.979899,

Now,

P(Y > 76) = P(Y - mean > 76 - mean)

                 = P( \frac{( Y- mean)}{\frac{S.D}{\sqrt{N} } })) > \frac{( 76- mean)}{\frac{S.D}{\sqrt{N} } })

                 = P(Z > \frac{( 76- mean)}{\frac{S.D}{\sqrt{N} } })

                 = P(Z > \frac{( 76- 69.7)}{1.979899 }))

                 = P(Z > 3.182)

                 = 1 - P(Z ≤ 3.182)

                 = 0.0007

⇒P(Y > 76) = 0.0007

6 0
3 years ago
What are the next two terms in the pattern 3,6,5,10,9,18,17...?
sleet_krkn [62]

the problem is a pattern that multiplies by two and subtracts one each time.

3x2=6 6-1=5 5x2=10 10-2=9 9x2=18 18-1=17 17x2=34 34-1=33


6 0
3 years ago
Read 2 more answers
Find the area of the figure sides meet at right angles
amm1812

Answer:

there is no figure

Step-by-step explanation:

attach a photo first

6 0
3 years ago
What fraction is equivalent to 3/9​
cluponka [151]

Answer:

There are infinity equivalent fractions to 3/9

Step-by-step explanation:

1 /3, 2 /6, 3/ 9, 4 /12, 5/ 15, 6 /18, 7/ 21, 8/ 24, 9 /27, 10/ 30, 11/ 33, 12/ 36, 13/ 39, 14 /42, 15 /45..........

7 0
3 years ago
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