Question

(x+4)^2-(x+2)(x-2)=20

Answer 1

⇒x²+ 4² - x²+ 2x - 2x + 4 = 20

⇒ x² - x² + 2x - 2x + 4² + 4 = 20

⇒ 16 + 4 = 20

⇒ 20 = 20

RHS = LHS hence proved

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Answer 2

Answer:

x = 0

Step-by-step explanation:

(a + b)² = a² +2ab + b²

(a +b)(a -b)= a² - b²

(x + 4)² - (x + 2 )(x - 2) = 20

x² + 2*4 *x + 4² - [x² - 2²] = 20

x² + 8x + 16 - [x² - 4]  = 20

x² + 8x + 16 - x²  + 4   = 20                 {(-1) is distributed x² and (-4)²}

x² - x² + 8x + 16 + 4     = 20 {Combine like terms}

                      8x + 20   = 20

                           8x      = 20 - 20

                               8x   = 0

x = 0