Given:
The population, P, of six towns with time t in years are given by the following exponential equations:
(i) 
(ii) 
(iii) 
(iv) 
(v) 
(vi) 
To find:
The town whose population is decreasing the fastest.
Solution:
The general form of an exponential function is:
Where, a is the initial value, b is the growth or decay factor.
If b>1, then the function is increasing and if 0<b<1, then the function is decreasing.
The values of b for six towns are 1.08, 1.12, 0.9, 1.185, 0.78, 0.99 respectively. The minimum value of b is 0.78, so the population of (v) town is decreasing the fastest.
Therefore, the correct option is b.
Ur output value is f(x).....so to do this problem u need to sub in 2/3 for f(x) and solve for the input value which is x
f(x) = -1/3x + 7
2/3 = -1/3x + 7 ...multiply everything by 3
2 = -x + 21
2 - 21 = - x
- 19 = -x
19 = x <== ur output
Answer:
Given:
mean, u = 6.2
sample size, n = 180
Sample mean, X' = 6.3
s.d 
= 0.9
Significance level = 0.05
The null and alternative hypothesis will be:
H0 : u = 6.2
H1 : u > 6.2
Degree of freedom = 180 - 1 = 179
Using t table, the t critical value,
t> t(0.05, 179) = 1.6534
The test statistic:
Since the test statistic(t calculated value) 1.4907 < t critical value (1.6534), we fail to reject the null hypothesis H0.
35=(5+2)+4
35=7+4
35=11
false so their is no answer
The answer is 8. I explain it to you?
