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labwork [276]
3 years ago
7

Is -14/3 greater than -4

Mathematics
2 answers:
ser-zykov [4K]3 years ago
4 0

Answer:

greater then

Step-by-step explanation:

disa [49]3 years ago
3 0

Answer:

No because it -4.6 and the other one is only -4

-4.6<-4

You might be interested in
True or false to begin an indirect proof, you assume the opposite of what you intend to prove is true
damaskus [11]

Answer:

true

Step-by-step explanation:

you must assume its false and if said statement leads to an impossibility then its proved to be true

7 0
3 years ago
Read 2 more answers
The probability of winning a particular game at the Game Place is 14 1/4 . Find the odds against winning the game.
Zinaida [17]
ANSWER

\frac{1}{3}



EXPLANATION

We want to find an odds ratio from a given probability, which is


\frac{1}{4}


We subtract the numerator 1 from the denominator 4 to obtain


4- 1= 3


The answer is the number of unfavorable outcomes. 

The Odds can then be expressed as

1 : 3


The ratio of favourable outcomes to unfavorable outcomes.


Or

\frac{1}{3}




6 0
3 years ago
If the sum of the zereos of the quadratic polynomial is 3x^2-(3k-2)x-(k-6) is equal to the product of the zereos, then find k?
lys-0071 [83]

Answer:

2

Step-by-step explanation:

So I'm going to use vieta's formula.

Let u and v the zeros of the given quadratic in ax^2+bx+c form.

By vieta's formula:

1) u+v=-b/a

2) uv=c/a

We are also given not by the formula but by this problem:

3) u+v=uv

If we plug 1) and 2) into 3) we get:

-b/a=c/a

Multiply both sides by a:

-b=c

Here we have:

a=3

b=-(3k-2)

c=-(k-6)

So we are solving

-b=c for k:

3k-2=-(k-6)

Distribute:

3k-2=-k+6

Add k on both sides:

4k-2=6

Add 2 on both side:

4k=8

Divide both sides by 4:

k=2

Let's check:

3x^2-(3k-2)x-(k-6) \text{ with }k=2:

3x^2-(3\cdot 2-2)x-(2-6)

3x^2-4x+4

I'm going to solve 3x^2-4x+4=0 for x using the quadratic formula:

\frac{-b\pm \sqrt{b^2-4ac}}{2a}

\frac{4\pm \sqrt{(-4)^2-4(3)(4)}}{2(3)}

\frac{4\pm \sqrt{16-16(3)}}{6}

\frac{4\pm \sqrt{16}\sqrt{1-(3)}}{6}

\frac{4\pm 4\sqrt{-2}}{6}

\frac{2\pm 2\sqrt{-2}}{3}

\frac{2\pm 2i\sqrt{2}}{3}

Let's see if uv=u+v holds.

uv=\frac{2+2i\sqrt{2}}{3} \cdot \frac{2-2i\sqrt{2}}{3}

Keep in mind you are multiplying conjugates:

uv=\frac{1}{9}(4-4i^2(2))

uv=\frac{1}{9}(4+4(2))

uv=\frac{12}{9}=\frac{4}{3}

Let's see what u+v is now:

u+v=\frac{2+2i\sqrt{2}}{3}+\frac{2-2i\sqrt{2}}{3}

u+v=\frac{2}{3}+\frac{2}{3}=\frac{4}{3}

We have confirmed uv=u+v for k=2.

4 0
3 years ago
School is Tomorrow I need help
german

Answer:

is their any way I can get some more info on this problem


Step-by-step explanation:


6 0
3 years ago
I need help please ..
koban [17]

A is 18

B is 162

C is 18

D is 162

4 0
3 years ago
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