Look at the picture.
To find the area of triangle DBC we need to find its base, x, and its height, h.
Triangle ABC is a right triangle, so using the Pythagorean theorem we can find x.

Now look at triangles ABC and DBH. They both are right triangles and have the same angle α. That means they're similar and their corresponding sides are proportional. The ratio of the side opposite to angle α to the hypotenuse is the same in both triangles - so the ratio of h to 1 is the same as the ratio of 3 to 5.

The base x is 4, the height h is 3/5. Calculate the area:

The area of triangle DBC is 6/5.
Cpctc because corresponding parts of congruent triangles are congruent. <span />
Its probably my computer, but your attachment went to a page that said, page not found...srry...:(
Answer: B 6^-2
Step-by-step explanation: because it is
Answer: Choice C
x/w and z/(y+v)
======================================================
Explanation:
All answer choices have that first fraction with a denominator of w. This implies that AB = w is the hypotenuse. This only applies to triangle ABD.
Focus on triangle ABD. It has an opposite leg of AD = x, when the reference angle is ABD (or angle B for short).
So we can say sin(ABD) = opposite/hypotenuse = AD/AB = x/w
x/w is one of the answers
-----------
Also note how y+v is the same for each denominator in the second fraction. y+v is the hypotenuse of triangle ABC. When the reference angle is ABD (aka angle ABC), the opposite side of this same triangle is AX = z
Therefore,
sin(ABD) = sin(ABC) = opp/hyp = AC/BC = z/(y+v)
z/(y+v) is the other answer
Side note: triangle ACD is not used at all.