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Bingel [31]
3 years ago
11

10m3 of air weigh 13 kg. Chapter Reference c How much does the air weigh in a room 4.2m long, 3.5m wide, and 2.6m high?

Mathematics
1 answer:
Zarrin [17]3 years ago
5 0

Answer:

The air weight in a room is 49.69 kg.

Step-by-step explanation:

It is given that the room is 4.2m long, 3.5m wide, and 2.6m high. It is also given that 10 m³ of air weigh 13 kg.

The formula to find the volume of cuboid is,

V=l\times b\times h

V=4.2\times 3.5\times 2.6

V=38.22

The volume of room is 38.22 m³.

Since it is given that, 10 m³ of air weigh 13 kg. So,

1 m^3=\frac{13}{10}kg

1 m^3=1.3kg

So the air weight in the room is,

\text{Air weight}=1.3\times 38.22

\text{Air weight}=49.686\approx 49.69

Therefore the air weight in a room is 49.69 kg.

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olga_2 [115]

}

Answer:B

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8 0
2 years ago
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A rectangular parking lot has an area of 2/3 of a square kilometer. The width is 1/2 of a kilometer. What is the length, in kilo
jeka57 [31]
Area = length x width
 replace the known information into the equation:

area = 2/3
width = 1/2

so now the formula looks like:

2/3  = 1/2 x L

to solve for L we divide both sides by 1/2

L = 2/3 / 1/2 which  = 2/3 * 2/1 = 4/3 = 1 and 1/3 km
6 0
3 years ago
Write a expression for j less than 113
kiruha [24]
So you just need to use the crocodile signs < or >
As j is less than 113 we put j on the smaller side and 113 on the bigger side to make:
j<113
4 0
3 years ago
the elephants at the norfolk zoo are fed 1/2 a barrel of corn each day. the buffalo are fed 7/10 as much corn as the elephants.
maksim [4K]

7/20 barrels of corn are the buffalo fed each day.

How to solve word problems?

It's actually fairly easy to solve word problems using a tried-and-true step-by-step approach.

  • Aloud to yourself, read the issue.
  • Make a Drawing.
  • Ask yourself, "What am I looking for?"
  • List the items that have been provided.
  • Locate the key phrases.
  • Solve.
  • Verify your work.

Here are some actions to take:

  1. Recognize the issue, including all the terminology used to describe it. Recognize what you need to look for, Recognize the issue's context.
  2. Convert the issue into an equation. Give the unknown a variable (or variables) to symbolize, Indicate exactly what the variable stands for.
  3. Put the strategy into action and find a solution.

Given:

Elephants at the Norfolk zoo are fed = 1/2

Buffalo are fed 7/10 as much corn as the elephants = 7/10 * Elephants fed

= 7/10 * 1/2

= 7/20

Hence, 7/20 barrels of corn are the buffalo fed each day.

To know more about word problems check the below link:

brainly.com/question/13818690

#SPJ4

4 0
1 year ago
The sum of three numbers in <br> g.p. is 21 and the sum of their squares is 189. find the numbers.
sashaice [31]
Let the three gp be a, ar and ar^2
a + ar + ar^2 = 21 => a(1 + r + r^2) = 21 . . . (1)
a^2 + a^2r^2 + a^2r^4 = 189 => a^2(1 + r^2 + r^4) = 189 . . . (2)
squaring (1) gives
a^2(1 + r + r^2)^2 = 441 . . . (3)
(3) ÷ (2) => (1 + r + r^2)^2 / (1 + r^2 + r^4) = 441/189 = 7/3
3(1 + r + r^2)^2 = 7(1 + r^2 + r^4)
3(r^4 + 2r^3 + 3r^2 + 2r + 1) = 7(1 + r^2 + r^4)
3r^4 + 6r^3 + 9r^2 + 6r + 3 = 7 + 7r^2 + 7r^4
4r^4 - 6r^3 - 2r^2 - 6r + 4 = 0
r = 1/2 or r = 2
From (1), a = 21/(1 + r + r^2)
When r = 2:
a = 21/(1 + 2 + 4) = 21/7 = 3
Therefore, the numbers are 3, 6 and 12.
3 0
3 years ago
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