Rotate the triangle 180 degrees around the origin

Martha is constructing the circumscribed circle for△RST. She has already used her compass and straightedge to complete the part

lianna [129]

Place the point of the compass on the intersection of AB and CD and extend the compasses to point R.

3 0

3 years ago

Read 2 more answers

At Western University the historical mean of scholarship examination scores for freshman applications is 900. A historical popul

dmitriy555 [2]

Answer:

The interval is [910.053; 959.946]

p-value 0.00596

Decision: Reject null hypothesis.

Step-by-step explanation:

Hello!

You need to make a 95% Confidence Interval for the population mean of scholarship examination scores for the freshman.

It is known to be μ= 900 and the assistant dean wants to test if it changed.

The study variable is:

X: -scholarship examination score of one applicant.

population variance is known as σ²= (180)²

Assuming that the variable has a normal distribution the formula for the interval is:

X[bar] ± $Z_{1-\alpha /2}$ * $\frac{S}{\sqrt{n} }$

935 ± 1.96* $\frac{180}{\sqrt{200} }$

The interval is [910.053; 959.946]

To test if the examination scores have changed the hypothesis is:

H₀: μ = 900

H₁: μ ≠ 900

α: 0.05

To use a Confidence Interval the following conditions should be met:

1) Both the test and the interval should be made for the same parameter.

2) The hypothesis has to be two_tailed

3) Confidence level 1 - α and significance level α should be complementary.

To make the decision you have to see if the value given to the population mean in the null hypothesis is contained or not by the interval.

If the value is contained by the interval, you do not reject the null hypothesis.

If the value is not contained by the interval, then the decision is to reject the null hypothesis.

Since 900 is not contained by the 95% Confidence interval [910.05; 959.95], the decision is to reject the null hypothesis. This means that the scholarship examination scores of freshman applications have changed.

To calculate the p-value you have to know the value of the statstic under the null hypothesis:

Z= $\frac{935-900}{\frac{180}{\sqrt{200} } }$ = 2.749 ≅ 2.75

p-value is

P(Z<2.75) + P(Z>2.75)= P(Z<2.75) + (1 - P(Z<2.75))= 0.00298+ (1 - 0.9702= 0.00596

I hope it helps!

4 0

3 years ago

We want to find the zeros of this polynomial:

fredd [130]

Answer:

x = -3 and x = -3/2

Step-by-step explanation:

After writing down the polynomial, split it; put a line between 3x^2 and -18x. Look and 2x^3 + 3x^2 and -18x - 27 separately and factor them both:

p(x) = 2x^3 + 3x^2 - 18x -27

p(x) = x^2(2x+3) -9(2x+3)

Now notice how x^2 and -9 have the same factor (2x+3). That means x^2 and -9 can go together:

p(x) = (x^2 - 9)(2x+3)

Factor it once more because there's a difference of squares:

p(x) = (x+3)(x-3)(2x+3)

Now just plug in whatever makes the each bracket equal 0:

x = -3, x = 3, and x = -3/2

Those are your zeros.

8 0

3 years ago

Complete the table dkskdsalaoakz

koban [17]

Answer:

2 gallons

32 pints

56 pins

10 gallons

Step-by-step explanation:

3 0

3 years ago

Find the Measure of B Topic: Inscribed Angles and Central Angles

Oxana [17]

Answer:

Option B

The measure of angle b is 75°

Step-by-step explanation:

Method 1

we know that

In a inscribed quadrilateral, the opposite angles are supplementary

so

∠a+60°=180° ------> equation A

∠b+105°=180° -----> equation B

To find the measure of angle b solve the equation B

∠b+105°=180°

Subtract 105° both sides

∠b+105°-105°=180°-105°

∠b=75°

Method 2

see the attached figure with letters to better understand the problem

we know that

The inscribed angle measures half that of the arc comprising

so

∠105°=(1/2)[arc ADC]

arc ADC=2*105°=210°

Find the measure of arc ABC

we know that

arc ABC+arc ADC=360° -----> by complete circle

arc ABC=360°-210°=150°

Find the measure of inscribed angle b

∠b=(1/2)[arc ABC]

substitute

∠b=(1/2)[arc 150°]=75°

8 0

3 years ago