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MaRussiya [10]
3 years ago
14

Rotate the triangle 180 degrees around the origin

Mathematics
1 answer:
neonofarm [45]3 years ago
5 0
If you rotate the triangle 180 degrees around the origin I’ll only go half way of that triangle
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Asap and brainliest<br> 19) Solve. x + 4 = 10 A) x = 2 B) x = 3 C) x = 6 D) x = 14
san4es73 [151]
The answer is d. x=14.
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3 years ago
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-3x+4y<br> greater than equal to 15
QveST [7]
Depending on if you're solving for X or Y:

X less than or equal to 4y/3 -5

Y greater than or equal to 3x/4+15/4
8 0
2 years ago
The sum of 5 consecutive even numbers is 200 what is the fifth number in this sequence?
Tema [17]
Find the average of the numbers(the middle number) by dividing 200 by 5 to get 40. Since the numbers count by two, we would add four to get the value of the last number: 44.
7 0
3 years ago
What is the simplest form of 2160x8/60x2? Assume
Mazyrski [523]

Step-by-step explanation:

(2160×8)÷(60×2)

Or, 270÷120

or, 2.25.

therefore answer is 2.25

5 0
3 years ago
Families USA, a monthly magazine that discusses issues related to health and health costs, survey 19 of its subscribers. It foun
s344n2d4d5 [400]

Answer:

a

   $10,151   <  \mu  $11448.12

b

  n =  158

Step-by-step explanation:

From the question we are told that

    The  sample size is  n  =  19

    The  sample mean is  \= x  =$10,800

     The  standard deviation is  \sigma  =$1095  

    The  population mean is  \mu  =$225

     

Given that the confidence level is 99%  the level of significance is mathematically represented as

       \alpha  =  100 -99

      \alpha  = 1%

=>    \alpha =  0.01

Now the critical values of \alpha  = Z_{\frac{\alpha }{2} } is obtained from the normal distribution table as

        Z_{\frac{0.01}{2} } =  2.58

The reason we are obtaining values for \frac{\alpha }{2} is because \alpha is the area under the normal distribution curve for both the left and right tail where the 99% interval did not cover while \frac{\alpha }{2}  is the area under the normal distribution curve for just one tail and we need the  value for one tail in order to calculate the confidence interval

Now the margin of error is obtained as

     MOE  =  Z_{\frac{\alpha }{2} } *  \frac{\sigma }{\sqrt{n} }

substituting values

    MOE  =  2.58*  \frac{1095 }{\sqrt{19} }

     MOE  =  648.12

The  99% confidence interval for the population mean yearly premium is mathematically represented as

    \= x -MOE  <  \mu <  \= x +MOE

substituting values

   10800 -648.12  <  \mu <  10800 + 648.12

    10800 -648.12  <  \mu <  10800 + 648.12

   $10,151   <  \mu  $11448.12

The  largest sample needed is mathematically evaluated as

      n =  [\frac{Z_{\frac{\alpha }{2}    } *  \sigma }{\mu} ]

substituting values

       n =  [    \frac{ 2.58  *  1095}{225} ]^2

      n =  158

6 0
3 years ago
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