Depending on if you're solving for X or Y:
X less than or equal to 4y/3 -5
Y greater than or equal to 3x/4+15/4
Find the average of the numbers(the middle number) by dividing 200 by 5 to get 40. Since the numbers count by two, we would add four to get the value of the last number: 44.
Step-by-step explanation:
(2160×8)÷(60×2)
Or, 270÷120
or, 2.25.
therefore answer is 2.25
Answer:
a
$10,151
$11448.12
b

Step-by-step explanation:
From the question we are told that
The sample size is n = 19
The sample mean is
$10,800
The standard deviation is
$1095
The population mean is
$225
Given that the confidence level is 99% the level of significance is mathematically represented as
%
=> 
Now the critical values of
is obtained from the normal distribution table as

The reason we are obtaining values for
is because
is the area under the normal distribution curve for both the left and right tail where the 99% interval did not cover while
is the area under the normal distribution curve for just one tail and we need the value for one tail in order to calculate the confidence interval
Now the margin of error is obtained as

substituting values


The 99% confidence interval for the population mean yearly premium is mathematically represented as

substituting values


$10,151
$11448.12
The largest sample needed is mathematically evaluated as
![n = [\frac{Z_{\frac{\alpha }{2} } * \sigma }{\mu} ]](https://tex.z-dn.net/?f=n%20%3D%20%20%5B%5Cfrac%7BZ_%7B%5Cfrac%7B%5Calpha%20%7D%7B2%7D%20%20%20%20%7D%20%2A%20%20%5Csigma%20%7D%7B%5Cmu%7D%20%5D)
substituting values
![n = [ \frac{ 2.58 * 1095}{225} ]^2](https://tex.z-dn.net/?f=n%20%3D%20%20%5B%20%20%20%20%5Cfrac%7B%202.58%20%20%2A%20%201095%7D%7B225%7D%20%5D%5E2)
