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nordsb [41]
3 years ago
5

PLEASE HELP WILL AWARD BRAINLIEST:)

Mathematics
1 answer:
stealth61 [152]3 years ago
5 0

Answer:

x = 4 units

Step-by-step explanation:

By geometric mean theorem:

Length of perpendicular

=\sqrt{2\times 6}

=\sqrt{12}

Next, by Pythagoras theorem:

x^2 = 2^2 + (\sqrt {12})^2

\therefore x^2 = 4 + 12

\therefore x^2 = 16

\therefore x =\sqrt{ 16 }

\therefore x =4\: units

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F(x) = 3x²+5, what is f(-3)
dimulka [17.4K]

Answer:

32

Step-by-step explanation:

f(x) = 3x²+5

f(-3) = 3(-3)^2+5 = 27 + 5 = 32

7 0
3 years ago
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34699 rounded to the nearest ten thousand
Leya [2.2K]

Answer:

the answer is 30,000

Step-by-step explanation:

If the number is less than 5 you round down, if it is 5+ you round up

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3 years ago
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??????????????????????
svet-max [94.6K]

Answer:

  • see attached for a graph
  • solution: (x, y) = (-1, 3)

Step-by-step explanation:

The first line has a slope of -3 and a y-intercept of 0. It will go through the origin and the point (-1, 3).

The second line has a slope of 1 and a y-intercept of 4. It will go through the points (0, 4) and (-4, 0).

The solution to the system of equations is the point where the lines cross, (-1, 3).

6 0
3 years ago
Mystery number: The number is less than 190000 and greater than 180000.
Kipish [7]
The answer to it is    
180, 000 <n> 190, 000 
180,000 + 2000 = n = 5000-187, 000 
182,000 = n = 182, 000   
Or,  
 180, 000 <n> 190,000                     
 n + 5000= 187, 000                           n – 2000 = 180, 000 
 n= 187, 000- 5000                             n = 180, 000 + 2000 
 n= 182, 000                                       n= 182, 000 
6 0
4 years ago
David y Angie tienen dos cartulinas iguales. David corta la suya en 3 trozos iguales y Angie la corta en 7 trozos. Los dos usan
Bess [88]

Answer:

(i) David ha empleado \frac{2}{3} de la cartulina.

(ii) Angie ha empleado \frac{2}{7} de la cartulina.

(iii) David ha usado más cartulina.

Step-by-step explanation:

El problema indica que David y Angie emplean una cartulina del mismo tamaño cada uno. David corta la suya en 3 pedazos iguales, mientras que Angie obtiene 7 pedazos iguales. Finalmente, cada uno emplea dos de sus pedazos. A continuación, respondemos a las preguntas del enunciado:

(i) <em>¿Qué fracción de cartulina ha usado David?</em>

La fracción de cartulina empleada por David es igual a los pedazos utilizados divididos por el total de pedazos. Esto es:

x = \frac{2}{3}

David ha empleado \frac{2}{3} de la cartulina.

(ii) <em>¿Qué fracción de cartulina ha usado Angie?</em>

Aplicando el mismo procedimiento del punto anterior, tenemos que:

x = \frac{2}{7}

Angie ha empleado \frac{2}{7} de la cartulina.

(iii) <em>¿Quién ha usado más cartulina?</em>

La persona que ha usado la mayor cantidad de cartulina es aquella que tiene el menor denominador. Por tanto, David ha usado más cartulina.

7 0
3 years ago
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