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Lady bird [3.3K]
3 years ago
8

For each of the situations described below,give an example(if it’s possible) or explain why it’s not possible.

Mathematics
1 answer:
Rina8888 [55]3 years ago
4 0

Step-by-step explanation:

a) If the given set of vectors does not span \mathbb{R}^{3} , it means the number of linearly independent vectors are less than 3. So by adding one or more linearly independent vectors with respect to existing vectors, we can convert the set to basis and basis always spans vector space.

eg. S= \left \{ (1,0,0)^{T},(1,2,0)^{T} \right \} this set does not span \mathbb{R}^{3} . Since it has only two vectors and both vectors are linearly independent, so adding one linearly independent vector with respect to the vectors of S viz. (0,0,1)^{T} can span whole \mathbb{R}^{3}.

b) It is not possible. Since if a set of vectors is linearly dependent then after adding linearly independent vectors it will also linearly dependent i.e. addition of a linearly independent vector does not effect on the set.

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Emergency!
Lesechka [4]
Every single one of those expressions factor.  When factored, this is what we have: \frac{(3x-7)(x+3)}{(x+3)(x-2)} * \frac{(2x-7)(x+9)}{(3x-7)(2x+7)}.  After canceling out like factors, what we are left with is this: \frac{1x+9}{1x-2}.  That means that b = 9, c = 1, and d = -2
4 0
3 years ago
G(x)= l2xl +2<br><br> find domain and range
Romashka [77]

The domain of the function g(x)=l2xl +2 is all real numbers and the range is from (0,∞).

Given g(x)= l2xl +2

First of all we know that modulas gives two values for x<0 and x>=0.

The function g(x) if opened gives two values.

for x>=0 g(x)=2x+2

for x<0 g(x)=-2x+2

because we have not told about the description about x so we can put any value in the function.

So the domain is all real numbers.

Now when we take g(x)=2x+2 for x>=0

putting x=0 we get 2 and rest are positive values so the value of g(x) keeps increasing as we increase the value of x. So here range is [2,∞).

Now take g(x)=-2x+2 for x<0

putting smallest number starting from zero but not 0 we will get a number near to 0 but not zero and because when a negative number multiplies with -2 it becomes positive and increase the value of g(x) so here the range becomes (0,∞).

When we talk about overall range it will be [2,∞) ∪(0,∞)

it will be (0,∞).

Hence the domain of the function g(x) is all real numbers and range is from 0 to infinity.

Learn more about domain and range at brainly.com/question/2264373

#SPJ10

3 0
2 years ago
I need help fast thanks
Galina-37 [17]

Answer:

In the explanation

Step-by-step explanation:

a) Multiply the second equation by 2, subtract both lines. You get x = -3. Plug this in to get y, y = -2

b) Multiply the first equation by 2, add both lines. You get x = 8. Plug this in to get y, y = -3

c) Multiply the first equation by 5, subtract both lines. You get y = 1. Plug this in to get x, x = -3

d) Multiply the first equation by 2 and the second one by 3, add both lines. You get x = 1. Plug this in to get y, y = 4

Hope this helps!

7 0
3 years ago
Is x+1/2=x-1/2 true?
Sedaia [141]

\frac{x+1}{2}=\frac{x-1}{2} is not true

Step-by-step explanation:

We need to find if \frac{x+1}{2}=\frac{x-1}{2} is true?

Solving:

\frac{x+1}{2}=\frac{x-1}{2}

Cross Multiplying

2(x+1)=2(x-1)

2x+2=2x-2

2x-2x=-2-2

0=-4

Since both sides of the equation are not equal, so there is no solution.

So, \frac{x+1}{2}=\frac{x-1}{2} is not true.

Keywords: Solving Equations

Learn more about Solving Equations at:

  • brainly.com/question/1563227
  • brainly.com/question/2403985
  • brainly.com/question/11229113

#learnwithBrainly

8 0
3 years ago
Which of the following is the correct factorization of the polynomial below?
Yuliya22 [10]
The answer is D. The polynomial is irreducible because 12 can’t be squared.
7 0
3 years ago
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