Answer: When y = -4, x = -10.
Explanation:
The equation for direct variation is y = kx^n, where k is the constant of variation. n is the exponent above the x value, but since this problem doesn’t involve exponents greater than one, we can ignore it.
First, find k.
y = kx
6 = k*15
k = 6/15 or 2/5
Now, we can solve for any x or y input. Let’s find x when y = -4.
y = kx
-4 = 2/5 * x
(to cancel out the fraction, multiply each side of the equation by its reciprocal, 5/2)
x = -4 * 5/2
x = -20/2
x = -10
Answer:
line1:y=2x+3
Gradient1=2
Let line2 be the line passes through (-4,1)and perpendicular to line1.
Because line2 and line1 are perpendicular, (gradient of line2) (gradient of line1) =-1
Gradient of line2=-1/2
Equation of line2:y-y1 =m(x-x1)
:y-1 =(-1/2)[x-(-4)]
:(y-1)(-2)=(x+4)
:-2y+2 =x+4
:-2y+2-x-4=0
:-x-2y-2 =0
:x+2y+2 =0
*notes:gradient=m
2 over 45 just so that you know
I thnk 83 if the year has 365 days
(2x24)+(2x42)
I am not sure
