Correct question:
An elevator in a mine shaft is stopped at 25 feet below ground level. And then travels 28 feet downward. What equation can be written to find the final position in feet of the elevator in relations to ground level?
Answer:
-53 feets
Step-by-step explanation:
Initial stop point = 25 feets below ground level
Further distance traveled = 28 feets below ground level
Final position in feet = Initial stop point + further distance traveled
Note : distances or point traveled below ground level or downward is represented as negative.
Final position in feets = (-25)feets + (-28)feets
Final position in feets = - 53 feets
The answer is 5.8 because you find the difference on the x axis and you can’t have a negative distance so yea 5.8
Answer:
It has no solution because the two lines would never meet since they have the same slope of -3
Answer:
Step-by-step explanation:
To solve this problem, we need to multiple 
and -2 by 
and add the results together:
Adding the two together give the following:
