![\bf \textit{volume of a sphere}\\\\ V=\cfrac{4\pi r^3}{3}~~ \begin{cases} r=radius\\ -----\\ V=972\pi \end{cases}\implies 972\pi =\cfrac{4\pi r^3}{3}\implies \cfrac{3\cdot 972\pi }{4\pi }=r^3 \\\\\\ 729=r^3\implies \sqrt[3]{729}=r\implies \boxed{9=r}](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Bvolume%20of%20a%20sphere%7D%5C%5C%5C%5C%0AV%3D%5Ccfrac%7B4%5Cpi%20r%5E3%7D%7B3%7D~~%0A%5Cbegin%7Bcases%7D%0Ar%3Dradius%5C%5C%0A-----%5C%5C%0AV%3D972%5Cpi%20%0A%5Cend%7Bcases%7D%5Cimplies%20972%5Cpi%20%3D%5Ccfrac%7B4%5Cpi%20r%5E3%7D%7B3%7D%5Cimplies%20%5Ccfrac%7B3%5Ccdot%20972%5Cpi%20%7D%7B4%5Cpi%20%7D%3Dr%5E3%0A%5C%5C%5C%5C%5C%5C%0A729%3Dr%5E3%5Cimplies%20%5Csqrt%5B3%5D%7B729%7D%3Dr%5Cimplies%20%5Cboxed%7B9%3Dr%7D)
now, recall that a diameter is twice as long as the radius, so the diameter is 2r.
Step-by-step explanation:
Rewrite the expression 1/x^2/3 in the form x^nRewrite the expression 1/x^2/3 in the form x^n
The answer is D
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Answer:
C and D
Step-by-step explanation:
2x^2 + 7x + 6
(2x + 3)(x+2)
x = -3/2 = -1.5
x = -2