Answer:
2196 fish
Step-by-step explanation:
Weight of fish that the killer whale might eat in a month (30 days) = 14,000 lb
Weight of the fish that killer whale might eat in a day = 
lb.
Average weight of the fish that killer whale eats = 3.4 oz
Since,
1 pound(lb) = 16 ounces(oz)
So,
Weight of the fish that killer whale might eat in a day in ounces(oz) = 
oz
Since, a certain fish weighs 3.4 oz, in order to find the number of fish that killer whale must eat, we must divide the total weight in ounces by 3.4 ounces.
So, the number of fish that killer whale would eat = 
fish
Thus, the killer whale needs to eat 2196 fish.
Answer:
204.55
Step-by-step explanation:
1 mile per hour is 0.489 yards per second
Ok so we'll go ahead and solve for y first - we just need to get it alone on one side of the equal sign
Step 1: subtract 2x from each side
2x - 7y - 2x = 19 - 2x
This cancels out the 2x on the left, giving us
-7y = 19 - 2x
Step 2: divide both sides by -7
= 
+ 
This gives us
y = -19/7 + 2x/7
That should be your answer for the first question. Now solving the next parts are easy. All you need to do is plug in x.
When x = -3
y = -19/7 + 2x/7
y = -19/7 + 2(-3)/7
y = -19/7 - 6/7
y = -25/7
When x = 0
y = -19/7 + 2x/7
y = -19/7 + 2(0)/7
y = -19/7
When x = 3
y = -19/7 + 2x/7
y = -19/7 + 2(3)/7
y = -19/7 + 6/7
y = -13/7
Hope that helps! Feel free to ask if I can help with anything else :)
Answer:
a.) 18000 x (0.88)^x
x=number of years
b.) value after 10 yrs is represented by
18000 x (0.88)^10 = about $5013
Step-by-step explanation:
Answer:
idk how to do that try to slove it
but I didn't get right answer
