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Bond [772]
3 years ago
12

Would someone help me understand this type of math

Mathematics
1 answer:
Svetlanka [38]3 years ago
6 0
I never understand that
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Find d: d= |5 1 -1 10|
alekssr [168]

Answer:

Step-by-step explanation:

8 0
2 years ago
PLEASE HELP!! :( <br> 6th grade math ( I suck at math)
agasfer [191]

Answer:

Width              Length

5                        8.7

7.9                    11.6

9                        12.7

11.3                     15.0

13                      16.7

Step-by-step explanation:

If they gave you the width, you add 3.7 to get the length.

If they gave  you the length, you subtract 3.7 to get the width.

4 0
3 years ago
Read 2 more answers
Please help. Dont put a random answer plz.
Alenkasestr [34]

Answer:

Explination:

Work:

5 0
3 years ago
Nigel wants to average 85% on his four tests. He got 77%, 89%, 78% on his first three tests. What does he need to get on his las
Arte-miy333 [17]

Answer:

He needs to get 96%

Step-by-step explanation:

Add 96 89 77 and 78 together and divide by 4, it should be 85

4 0
3 years ago
Use a matrix equation to solve the system of linear equations. left brace Start 2 By 1 Matrix 1st Row 1st Column 2nd Row 1st Col
natali 33 [55]

Answer:

\left[\begin{array}{ccc}3&-1&\\-1&1/2\\\end{array}\right]

Step-by-step explanation:

The matrix system for the linear equations: x + 2y = 8, 2x + 6y = 9

\left[\begin{array}{ccc}1&2&\\2&6\\\end{array}\right] \left[\begin{array}{ccc}x\\y\end{array}\right] = \left[\begin{array}{ccc}8\\9\end{array}\right]

To get the coefficient of x and y, the inverse of the first matrix (let the first matrix be A) must be known.

A^{-1} = (1 / determinant of A) x Adjoint of A

the determinant of A = (1 x 6) - (2 x 2) = 6 - 4 = 2

Adjoint of A = \left[\begin{array}{ccc}6&-2&\\-2&1\\\end{array}\right]

A^{-1}= \frac{1}{2} \left[\begin{array}{ccc}6&-2\\-2&1\end{array}\right] = \left[\begin{array}{ccc}3&-1&\\-1&1/2\\\end{array}\right]

4 0
2 years ago
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