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zepelin [54]
3 years ago
12

Solve the equation 7x-3(x-6)=30

Mathematics
2 answers:
Alinara [238K]3 years ago
8 0

Answer:

x=3

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

7x−3(x−6)=30

7x+(−3)(x)+(−3)(−6)=30(Distribute)

7x+−3x+18=30

(7x+−3x)+(18)=30(Combine Like Terms)

4x+18=30

4x+18=30

Step 2: Subtract 18 from both sides.

4x+18−18=30−18

4x=12

Step 3: Divide both sides by 4.

4 divided by 12 =3

4 divided 4 = 1

x=3

garri49 [273]3 years ago
7 0

Answer:

The answer is x = 3

Step-by-step explanation:

7x - 3(x-6) =30

7x -3x+18=30

4x= 30-18

4x=12

x=12/4

x=3

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For the figures below, assume they are made of semicircles, quarter circles and squares. For each shape, find the area and perim
Marina86 [1]

Area of the shaded region $=36(\pi -2) square cm

Perimeter of the shaded region =6 (\pi + 2\sqrt 2) cm

Solution:

Radius of the quarter of circle = 12 cm

Area of the shaded region = Area of quarter of circle – Area of the triangle

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Area of the shaded region $=36(\pi -2) square cm

Using Pythagoras theorem,

AC^2=AB^2+BC^2

AC^2=12^2+12^2

AC^2=288

Taking square root on both sides of the equation, we get

AC= 12\sqrt 2 cm

Perimeter of the quadrant of a circle = \frac{1}{4} \times 2\pi r

                                                             $=\frac{1}{4} \times 2 \times \pi \times 12

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Perimeter of the shaded region = 6 \pi + 12\sqrt 2 cm

                                                    =6 (\pi + 2\sqrt 2) cm

Hence area of the shaded region $=36(\pi -2) square cm

Perimeter of the shaded region =6 (\pi + 2\sqrt 2) cm

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Step-by-step explanation:

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